The histograms show the number of new subscribers in one month by age group for three newspaper. which statement is best support
ed by the data in the histograms?
A: the chronicle had more new subscribers for each age group than either the times the daily.
B: there were 1000 fewer new subscribers in the 20-29 and the 30-39 age groups combined for the chronicle than there were in these same age groups for the times and the daily combined
C: the chronicle had exactly 50,500 new subscribers for all age groups combined
D: there were three times as many new subscribers in the 20-29 and the 30-39 age groups combined for the chronicle than in the 20-29 age group for the times.
A: the chronicle had more new subscribers for each age group than either the times the daily.
B: there were 1000 fewer new subscribers in the 20-29 and the 30-39 age groups combined for the chronicle than there were in these same age groups for the times and the daily combined
C: the chronicle had exactly 50,500 new subscribers for all age groups combined
D: there were three times as many new subscribers in the 20-29 and the 30-39 age groups combined for the chronicle than in the 20-29 age group for the times.
2 answers:
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Answer:
The sum of the two integers is 23
Step-by-step explanation:
Let one integer be x and the other integer be y
Then according to the statement "One positive integer is 3 greater than 4 times another positive integer.."
x be the integer that is One positive integer is 3 greater than 4 times another positive integer.
Then
x= 3+4y----------------------------------(1)
Product of the two integer is 76, this can written as
substituting the values of x from eq(1)
Solving the quadratic equation equation we get
here
a = 4
b= 3
c = -76
susbtituting the above values in the formula
y= 4 y = −4.75
Since in the question it is given that it is a positive integer
so y = 4
substituting y=4 in eq (1) we get,
x= 3+4(4)
x= 3+16
x= 19
The sum of the two integers
=> x + y
=> 19+4
=>23