<em>Because OP only asked for a clarification of the problem statement: </em>
You are asked to find the green area. (Hint: divide the green area into rectangles and right triangles, because you know their area.)
Answer:
10. (5, 6)
11. (1, 2)
12. (7, 8)
13. (10, 11)
14. (27, 28)
15. (11, 12)
Step-by-step explanation:
If you're not familiar with the squares of small integers, your calculator can help you figure this.
10. √28 ≈ 5.291 . . . . between 5 and 6
11. √3 ≈ 1.732 . . . . between 1 and 2
12. √59 ≈ 7.681 . . . . between 7 and 8
13. √115 ≈ 10.724 . . . between 10 and 11
14. √772 ≈ 27.785 . . . . between 27 and 28
15. √140 ≈ 11.832 . . . . between 11 and 12
If the third term of the aritmetic sequence is 126 and sixty fourth term is 3725 then the first term is 8.
Given the third term of the aritmetic sequence is 126 and sixty fourth term is 3725.
We are required to find the first term of the arithmetic sequence.
Arithmetic sequence is a series in which all the terms have equal difference.
Nth term of an AP=a+(n-1)d
=a+(3-1)d
126=a+2d--------1
=a+(64-1)d
3725=a+63d------2
Subtract second equation from first equation.
a+2d-a-63d=126-3725
-61d=-3599
d=59
Put the value of d in 1 to get the value of a.
a+2d=126
a+2*59=126
a+118=126
a=126-118
a=8
=a+(1-1)d
=8+0*59
=8
Hence if the third term of the arithmetic sequence is 126 and sixty fourth term is 3725 then the first term is 8.
Learn more about arithmetic progression at brainly.com/question/6561461
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Im sorry. I need the options to answer this...
But if you want to answer this your self just take all your options and replace x with -2 and use PEMDAS to find if it equals 0 or not.
Answer:
11+12+13+14=50
Step-by-step explanation:
Just estimate. We know that 15 times 4 = 60, so it has to be less than that. We know that 10 times 4 is 40, so it has to be in that range. Just do trial and error to find the exact answer. I'm editing this now and I realized that I didn't answer the question. I don't know how to write the equation using N but the first integer is 11.