We are asked to transform the equation <span>3x^2+3x+2y=0 into the standard form by applying the technique of completing the square .
</span><span>3(x^2+x +1/4) =-2y + 3/4
</span>3 (x +1/2)^2 = -2 (y -3/8)
-3/2 (x +1/2)^2 = (y -3/8)
this follows the standard from <span>y-b=A(x-a)^2</span>
Answer:
the top 2 and the left bottom corner
Step-by-step explanation:
the first one in the first row is a reflection
the second one in the first row is a rotation
the one on the left bottom corner just moved a unit
First, simplify the equation given into slope intercept form.
slope intercept form is y = mx + b, where b is the y intercept and m is the slope.
3x - 2y - 5 = 0
I would move the 2y to the other side.
3x - 5 = 2y
Then, since y can't have a coefficient, divide everything by 2;
y = 3/2x - 5/2
So there's your slope intercept form.
Point slope form is:
Where those with a subscript of 1 are part of the same point.
So you already known one point; -8, 8. I'll just do that as the pair with subscript 1. You know the slope as well from the slope intercept form; 3/2.
You can just plug those in.
y - 8 = 3/2 (x + 8)
Now to change this to general form.
First, distribute 3/2 to x and 8.
y - 8 = 3/2x + 12
-3/2x + y = 20
-3/2x + y - 20 = 0
Since there are no fractions, multiply everything by 2.
-3x + 2y - 40 = 0
Once at (-3,-10) is where they would intersect