Suppose both pairs of corresponding legs of two right triangles are congruent. Are the triangles congruent?

Henry buys 6 circus tickets for himself and five friends for a total of $174. Each friend pays Henry back for his or her ticket.

Deffense [45]

Answer:

$11

Step-by-step explanation:

According to the statement, you have that 6 tickets for the price of each ticket is equal to $174 and from that, you can determine the price of each ticket:

6*P=174

P= price of each ticket

P= 174/6= 29

Now, as it says that one of Henry's friends gives him two $20 bills, that means that he gives him $40 and you have to subtract the price of the ticket from that:

40-29= 11

The answer is that if one of Henry's friends gives him two $20 bills, Henry has to return $11.

5 0

3 years ago

Help meee ! look at the picture lol

Zigmanuir [339]

The answer is 2 bedsheets every 1 minute

8 0

3 years ago

Read 2 more answers

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

Step-by-step explanation:

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

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$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

Hint: sin is only positive in Quadrants I and II

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

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$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

Hint: sin and cos are only opposite signs in Quadrants II and IV

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

3 years ago

What is y = mx b for x?

makkiz [27]

Y=mx+b
minus b tboth sides
y-b=mx
divide both sides by m
$\frac{y-b}{m}=x$

7 0

3 years ago

Read 2 more answers

Scale on map is Lin 86 mi if actual distance is 35 mi . Between two cities how far apart on the map are they

Mrac [35]

Answer:

0.41 cm

Step-by-step explanation:

The scale on the map is 1 in 86 mi.

This means that, 1 cm on the map represents 86 miles in real life, or on earth.

Then we're told that in real life, a distance is 35 miles, and how far they are on the map.

If 1 cm equals 86 miles, then we can say that x cm equals 35 miles

1 cm ----> 86

x cm ----> 35

x * 86 = 35 * 1

x = 35 / 86

x = 0.41 cm

Therefore, they must be 0.41 cm farther or closer apart on the map scale.

5 0

2 years ago