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hoa [83]
3 years ago
9

Suppose both pairs of corresponding legs of two right triangles are congruent. Are the triangles congruent?

Mathematics
1 answer:
vredina [299]3 years ago
6 0

Answer:

<h3>7jhvnkkigvnj5dfjuscg77900744yj</h3>
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If the circumference of the circular base of a cylinder is doubled, how does the volume of the cylinder change?
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The volume of the cylinder would increase 
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Use the ratio table to solve the percent problem.
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Not quite sure what the ratio table is
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6x − 5 &gt; −29 Whats the answer???
marysya [2.9K]
6x - 5 > -29

Solve for x and thus it will be:

6x > -24

X > -4.

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8 0
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The radius of Venus is 3760.4 miles. What is the approximate volume of Venus?
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5 0
3 years ago
Celia has some cakes.
Vadim26 [7]

The carrot cakes are the fraction of the cake given by 1 - \frac{6}{7} multiplied by \frac{1}{3}

  • The fraction of the cakes that are carrot cakes is \underline {\dfrac{1}{21}}

<h3>How are the cakes evaluated as fractions?</h3>

The fraction of the cake that are chocolate cake = \dfrac{2}{3}

The fraction of the remaining cake that cheesecakes = \dfrac{6}{7}

The rest of the cakes = carrot cakes

Required:

The fraction of the cake that  are carrot cakes

Solution:

The fraction of the cakes that are not chocolate cake = 1 - \dfrac{2}{3} = \mathbf{ \dfrac{1}{3}}

The fraction of the remaining cakes that are cheesecake = \dfrac{6}{7} \times \dfrac{1}{3} = \mathbf{ \dfrac{6}{21}}

The fraction of the cake that are carrot cake = \dfrac{1}{3} - \dfrac{6}{7} \times \dfrac{1}{3} = \mathbf{\dfrac{1}{21}}

  • The fraction of the cakes that are carrot cake is \underline{\dfrac{1}{21}}

Learn more about fractions here:

brainly.com/question/3840488

5 0
2 years ago
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