Answer:
I don't get it but in my opinion I would say it's 4
Solving the complex number, we get the value of the missing value that is ‘a’ = -6
We have been given the expression as
|a – i| = √37 (1)
Which is an expression of complex number. The general expression of complex number is given as
z = x + iy
where x is the real part and iy is the imaginary part
To find the modulus value, the formula is given by,
|z| = |x + iy|
|z| = √[(real part)2 + (imaginary part)2]
|z| = √(x2 + y2)
According to the question, |z| = √37 (2)
Equating equation (1) and (2), we get
√(a2 + 1) = √37
(a2 + 1) = 37
a2 = 37 – 1
a2 = 36
a = √36
a = ±6
Now value of a can be 6 or -6. We have been given that the modulus is in third quadrant.
Hence the value will be negative. Therefore, the missing value will be -6.
Learn more about complex number here : brainly.com/question/5564133
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Cramer's Rule is a method that uses determinants to solve systems of equations that have the same number of equations as variables
Answer:
a. 2^(x-2) = g^(-1)(x)
b. A, B, D
Step-by-step explanation:
the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)
1. replace g(x) with y and solve for x
y = log₂(x) + 2
subtract 2 from both sides to isolate the x and its log
y - 2 = log₂(x)
this text is replaced by the second image -- it was marked as inappropriate
thus, 2^(y-2) = x
replace x with g^(-1)(x) and y with x
2^(x-2) = g^(-1)(x)
2. plug this in to points A, B, C, D, E, and F
A: (2,1)
plug 2 in for x
2^(2-2) = 2⁰ = 1 so this works
B: (4, 4)
2^(4-2) = 2²= 4 so this works
C: (9, 3)
2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work
(5, 8)
2^(5-2) = 2³ = 8 so this works
E: (3, 5)
2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work
F: (8, 5)
2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work
No because it has to be a even number to be divisible by 2 and same goes with 5 something has to x the 2 with the number like 2/4=2 because 2x2 is 4
