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2 years ago

Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following:

Mathematics

1 answer:

antoniya [11.8K]2 years ago

4 0

Answer:

The probability is 435/6,806

Step-by-step explanation:

Firstly, the total number of coins in the jar is

13 + 15 + 29 + 26 = 83

The probability of selecting a dime is 15/83

Now we want to grab a nickel

Since we already selected a dime and we did not replace it, the number of total coins in the jar will be 83-1 = 82

So the probability of selecting a nickel this time is

29/82

So the total probability of the event in the described order is;

15/83 * 29/82

= 435/6,806

You might be interested in

Jason rolls a fair number cube labeled 1 through 6, and then he flips a coin. What is the probability that he rolls a 3 and flip

qwelly [4]

The answer is 1/12

The chance of getting a 3 on a six-sided dice is 1/6

The possibility of getting heads on a two-sided coin is 1/2

6 multiplied by 2 is 12

1 multiplied by 1 is 1

Hope it helps!

3 0

2 years ago

Read 2 more answers

The volume of a right circular cone with radius r and height h is V = pir^2h/3.

Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9 and dr = 6.8 - 5.9 = 0.9

h = 4 and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b). The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47 and dr = 6.45 - 6.47 = -0.02

h = 10 and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0

2 years ago

20 POINTS AND BRAIN LIESTJ ulia s urveyed the pl ayers on her so ccer team to see how many hou rs each mem ber prac ticed during

lana66690 [7]

Answer:

the left side of the histogram is the mirror image of the right side.

6 0

2 years ago

You buy 4.5 pounds of bananas at $0.49 a pound. You hand the cashier a $20 bill. How much change will you get back

VARVARA [1.3K]

Answer:

You get 17.80 cents back

Step-by-step explanation:

4.5 times 0.49 is 2.20 cents

20 minus 2.20 is 17.80 dollars

4 0

2 years ago

An executive in the home construction industry is interested in how house size (House) is influenced by family income (Income),

Harman [31]

Answer:

Check the explanation

Step-by-step explanation:

(a)

P-value of income and size is 0.0003 and 0.0001 respectively. Both are less than 0.05 level of significance. So these are significant ot the model. Option D is correct.

(b)

The model is

House_size = -1.6335+0.4485*income + 4.2615*family_size -0.6517*school

Here we have income = 85600/1000 = 85.6

family_size = 6

school = 13

So the predicted house size is

House_size = -1.6335+0.4485*85.6 + 4.2615*6 -0.6517*13=53.855

the predicted house size (in hundreds of square feet) is 53.86. hence, option B is correct.

Here we have income = 100000/1000 = 100

family_size = 10

school = 16

So the predicted house size is

House_size = -1.6335+0.4485*100 + 4.2615*10 -0.6517*16=75.40

Residual : observed value- predicted value = 70 - 75.40 = -5.40

Option C is correct.

7 0

3 years ago