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Anna [14]
3 years ago
11

I need help with this

Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0

Answer:

y = - \frac{1}{2} x + 4

Step-by-step explanation:

Let us consider two points through which the line passes through

(x_1 , y _ 1 ) = ( 0 , 4 ) \ and \  (x_ 2 , y _ 2 ) = ( 4, 2 )

Step 1 : <em><u>Find slope of the line</u></em>

Slope, m_1 = \frac{rise}{run}  \\\\That \ is \ m_1 \ = \frac{y_2 - y _ 1}{x_2 - x_1}

                  = \frac{2 - 4}{4-0} \\\\=-\frac{2}{4}\\\\= - \frac{1}{2}

Step 2 : <em><u>Find equation of the line.</u></em>

<em><u /></em>(y - y _ 1) = m_ 1 (x - x_1)\\\\( y - 4) = - \frac{1}{2}(x - 0)\\\\y = -\frac{1}{2}x + 4<em><u /></em>

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2/7 × (-7/9) in decimal form
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Answer:  -\frac{2}{9}\quad \left(\mathrm{Decimal:\quad }\:-0.22222\dots \right)

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\frac{2}{7}\left(-\frac{7}{9}\right)

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If P(A)=.55, P(B)=.32 And P(AuB)=.70,
son4ous [18]

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A. 0.5313

B. 0.15

Step-by-step explanation:

Given:

P(A)=0.55\\ \\P(B)=0.32\\ \\P(A\cup B)=0.70

First , use formula

P(A\cup B)=P(A)+P(B)-P(A\cap B)

to find P(A\cap B):

0.70=0.55+0.32-P(A\cap B)\\ \\P(A\cap B)=0.55+0.32-0.70=0.87-0.70=0.17

A. Use formula

P(A|B)=\dfrac{P(A\cap B)}{P(B)}\\ \\P(A|B)=\dfrac{0.17}{0.32}=\dfrac{17}{32}=0.53125\approx 0.5313

B. Use formula

P(A'|B)=P(B)-P(A\cap B)=0.32-0.17=0.15

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