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mario62 [17]
3 years ago
13

Nancy and bill collect coins. Nancy has x coins. Bill has 6 coins fewer than times the number of coins nancy has. Write and simp

lify an expression for the total number of coins nancy and bill have
Mathematics
1 answer:
tino4ka555 [31]3 years ago
6 0

Answer:

Total number of coins Nancy and bill have = 6x - 5

Step-by-step explanation:

Nancy and bill collect coins. Nancy has x coins. Bill has 5 coins fewer than five times the number of coins Nancy has. Write and simplify an expression for the total number of coins Nancy and bill have . Simplify your answer .

Let

Number of Nancy's coins = x

Number of Bill's coins = 5x - 5

Total number of coins Nancy and bill have = Number of Nancy's coins + Number of Bill's coins

= x + (5x - 5)

= x + 5x - 5

= 6x - 5

Total number of coins Nancy and bill have = 6x - 5

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Use the graph or table to write a linear function that relates y to x.
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Answer:

x+2y=0

Step-by-step explanation:

7 0
3 years ago
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a right triangle has legs of length 3x m and 4x m and hypotenuse of length 75 m. find the lengths of the legs of the triangle
just olya [345]
It is a 3-4-5 right triangle

leg1 := 3x, leg2:=4x, hypotenuse:=5x

given hypotenuse = 75m
=> 5x=75
So, x= 75÷5 = 15
Therefore, leg1 = 3(15) = 45m.
leg2= 4(15) = 60m.
4 0
2 years ago
Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.
Sindrei [870]

Answer:

a) P(X=3) = 0.1

b) P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

c) P(X=4) = 0.3

d) P(X=0) = 0.2

e) E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

f) E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

Step-by-step explanation:

We have the following distribution

x      0     1     2   3   4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

P(X=3) = 0.1

Part b

We want this probability:

P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

Part c

For this case we want this probability:

P(X=4) = 0.3

Part d

P(X=0) = 0.2

Part e

We can find the mean with this formula:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

Part f

We can find the second moment with this formula

E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

4 0
3 years ago
Can anyone help with the last problem about The Difference Quotient of a Function
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Answer:

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Step-by-step explanation:

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2 years ago
An ice-skating competition lasted three days. Day one had an attendance of 16,390 people. Day two had an attendance of 16,550 pe
lana [24]

Answer:

Day\ 3 = 16237

Day\ 1 = 16390

Day\ 2 = 16550

Step-by-step explanation:

Given

Day\ 1 = 16390

Day\ 2 = 16550

Day\ 3 = 16237

Required

Order from least to greatest

Comparing 16390, 16550 and 16237.

The order of arrangement from least to greatest is:

16327, 16390 and 16550.

So, we have:

Day\ 3 = 16237

Day\ 1 = 16390

Day\ 2 = 16550

6 0
3 years ago
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