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sladkih [1.3K]
3 years ago
6

suppose a city with population 100,000 has been growing a rate of 4% per year. if this rate continues find the population of thi

s city in 10 years​
Mathematics
1 answer:
galina1969 [7]3 years ago
6 0

Answer:

f(x) = a(1 + r)x f(x) = 100000(1+0.04)^10 = 148,024 I believe

Step-by-step explanation:

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The image of RST in the graph shown below is rotated 90°counterclockwise around the origin to form R'S'T'.
Aleonysh [2.5K]

Answer:

Please check the explanation.

Step-by-step explanation:

Let suppose we have a point P(x, y) if we rotate our point 90 degrees counterclockwise about the origin, the new coordinates of the image of the point P can be obtained by switching 'x' and 'y' and making 'y' negative.

In other words,

P(x, y) → P'(-y, x)

From the given triangle ΔRST,

The coordinates of the point S is:

  • S(10, 1)

According to the rule, if we have a point S(10, 1), after rotations of 90 degrees counterclockwise about the origin, the new coordinates of the image of the point S(10, 1) will be:

S(10, 1) → S'(-1, 10)

Here,

S'(-1, 10)  is the image of the original point or pre-image point S(10, 1).

Therefore, the y-coordinate of the point S' is: 10

5 0
3 years ago
When 10 gallons of gasoline are put into a car's tank, the indicator goes from 1/8 of a tank to 3/4. What is the total capacity
juin [17]
It should be 16 gallons.
7 0
3 years ago
A box of light fixtures cost $43 if you had $600 and I bought is moving boxes as you could how much money would you have left
Mademuasel [1]

Answer:

13 Boxes with $41 left over

Step-by-step explanation:

$600/$43 = 13.9  (so she can buy 13 boxes of light fixtures)

$43 x 13 = $559

$600-$559=$41 left over


6 0
3 years ago
Which of the following equations must be true? A k +5 (3 – 1) = 15+ k B) 3+ 7k 21+ 3k C) 5 2k = 3K © 5 D) 5 (7 + k) = 35 + 5k​
Lina20 [59]

Answer:

D is the correct answer

im sure

7 0
3 years ago
How to find the derivative of e^3㏑(x²)
vovikov84 [41]
f(x)=e^{3\ln x^2}\\\\f'(x)=e^{3\ln x^2}\cdot\dfrac{3}{x^2}\cdot2x=e^{3\ln x^2}\cdot\dfrac{6}{x}=\dfrac{6e^{3\ln x^2}}{x}\\\\\\but\ e^{3\ln x^2}=e^{\ln (x^2)^3}=e^{\ln x^6}=x^6\ where\ x\neq0\\\\therefore\ f'(x)=6x^5
7 0
3 years ago
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