Explanation:
The given data is as follows.
Mass of ice dropped = 325 g
Initial temperature = = (30 + 273) K = 303 K
Final temperature = = (0 + 273) K = 273 K
Now, using density of water calculate the mass of ice as follows.
= 500 g
As the relation between heat energy, specific heat and change in temperature is as follows.
Q =
=
= 62750 J
Also, relation between heat energy and latent heat of fusion is as follows.
Q = m L
=
= 108300 J
Therefore, we require heat but we have 40774.95 J.
So,
=
= 188.4 g
Hence, the mass of ice = 325 g - 188.4 g
= 137 g
Therefore, we can conclude that 137 g of ice will still be present when the contents of the pitcher reach a final temperature.