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AURORKA [14]
3 years ago
15

Which method of heat transfer happens when heat is transferred from one object to another by electromagnetic rays?

Chemistry
2 answers:
tresset_1 [31]3 years ago
4 0

Answer:

The method of heat transfer between objects by electromagnetic rays is called radiation.

Explanation:

Radiation is a heat transfer method that takes place between objects trough electromagnetic rays. This phenomena occurs because of the movement of charged particles composing the materia. Radiation is one of the most important methods of heat transfer.

vredina [299]3 years ago
3 0
Heat<span> can be </span>transferred from one<span> place to </span>another<span> by three </span>methods<span>: conduction in solids, convection of fluids (liquids or gases), and </span>radiation<span> through anything that will allow </span>radiation<span> to pass. The </span>method<span> used to </span>transfer heat<span> is usually the </span>one<span> that is the most efficient.</span>
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A 5.76 liter sample of a gas at 22.00C mL 748 torr pressure was heated to a final volume of 17.28 liters, with the pressure rema
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Answer:

The final temperature was 612 °C

Explanation:

Charles's law relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, using a constant of direct proportionality. In this law, Charles says that at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T}=k

When you want to study two different states, an initial and a final one of a gas and evaluate the change in volume as a function of temperature or vice versa, you can use the expression:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

  • V1= 5.76 L
  • T1= 22 °C= 295 °K (Being 0°C=273°K)
  • V2=17.28 L
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Replacing:

\frac{5.76 L}{295 K} =\frac{17.28 L}{T2}

Solving:

T2 =\frac{17.28 L}{\frac{5.76 L}{295 K}}=\frac{17.28 L*295 K}{5.76 L}

T2= 885 °K = 612 °C

<u><em>The final temperature was 612 °C</em></u>

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