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AURORKA [14]
3 years ago
15

Which method of heat transfer happens when heat is transferred from one object to another by electromagnetic rays?

Chemistry
2 answers:
tresset_1 [31]3 years ago
4 0

Answer:

The method of heat transfer between objects by electromagnetic rays is called radiation.

Explanation:

Radiation is a heat transfer method that takes place between objects trough electromagnetic rays. This phenomena occurs because of the movement of charged particles composing the materia. Radiation is one of the most important methods of heat transfer.

vredina [299]3 years ago
3 0
Heat<span> can be </span>transferred from one<span> place to </span>another<span> by three </span>methods<span>: conduction in solids, convection of fluids (liquids or gases), and </span>radiation<span> through anything that will allow </span>radiation<span> to pass. The </span>method<span> used to </span>transfer heat<span> is usually the </span>one<span> that is the most efficient.</span>
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1a) consider the mixed aldol condensation reaction of 1-methylcyclopentane-1-carbaldehyde (shown below) and 3,3-dimethyl-2-butan
zubka84 [21]
Aldehydes and ketones having α-hydrogen atoms, undergoes aldol condensation, in present of base (NaOH). 

The initial product formed during this reaction is β-hydroxy alcohol, which then undergoes dehydration to form α,β-unsaturated aldehyde or ketone.

In present case, 3,3-dimethyl-2-butanone  has 2α-hyrogen atom, while methylcyclopentane-1-carbaldehyde has 1α-hydrogen atom. So the major product formed during cross aldol condensation reaction of these reactants is:
 5-hydroxy-4,4-dimethly-1-(2-methylcyclopentyl)pent-1-en-3-one. 

The complete reaction product formed is shown below. 

7 0
3 years ago
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Consider the reaction N2(g) + 2O2(g)2NO2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surr
zysi [14]

<u>Answer:</u> The value of \Delta S^o for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

N_2+2O_2\rightarrow 2NO_2

The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(2\times \Delta S^o_{(NO_2(g))})]-[(1\times \Delta S^o_{(N_2(g))})+(2\times \Delta S^o_{(O_2(g))})]

We are given:

\Delta S^o_{(NO_2(g))}=240.06J/K.mol\\\Delta S^o_{(O_2)}=205.14J/K.mol\\\Delta S^o_{(N_2)}=191.61J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(2\times (240.06))]-[(1\times (191.61))+(2\times (205.14))]\\\\\Delta S^o_{rxn}=-121.77J/K

Entropy change of the surrounding = - (Entropy change of the system) = -(-121.77) J/K = 121.77 J/K

We are given:

Moles of nitrogen gas reacted = 1.90 moles

By Stoichiometry of the reaction:

When 1 mole of nitrogen gas is reacted, the entropy change of the surrounding will be 121.77 J/K

So, when 1.90 moles of nitrogen gas is reacted, the entropy change of the surrounding will be = \frac{121.77}{1}\times 1.90=231.36 J/K

Hence, the value of \Delta S^o for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

7 0
3 years ago
HELP ASAP! GIVING BRAINLIEST!!<br><br> Why would a pendulum stop swinging? Where did the energy go?
kvasek [131]

Answer:

The pendulum would stop swinging because the kinetic energy would slow down for the friction is causing it to slow. The energy would go into potential energy.

7 0
3 years ago
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4.80 x 10^25 formula units pf calcium iodide (Cal2) will have what mass?
maw [93]

Answer:

mass CaI2 = 23.424 Kg

Explanation:

From the periodic table we obtain for CaI2:

⇒ molecular mass CaI2: 40.078  + ((2)(126.90)) = 293.878 g/mol

∴ mol CaI2 = (4.80 E25 units )×(mol/6.022 E23 units) = 79.708  mol CaI2

⇒ mass CaI2 = (79.708 mol CaI2)×(293.878 g/mol) = 23424.43 g

⇒ mass CaI2 = 23.424 Kg

7 0
3 years ago
Jonathan used the following soil triangle to identify a sample of soil as sandy clay. Which description of soil likely allowed J
Papessa [141]

Answer:

Mostly large grains, with a sticky texture, 55% sand, 40% clay, and 5% silt

Explanation: I took the test, hope it helps.

7 0
3 years ago
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