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sashaice [31]
2 years ago
6

Explain the difference between molecule and compound

Chemistry
1 answer:
nadya68 [22]2 years ago
8 0
Answer:
A molecule is a group of two or more atoms held together by chemical bonds. A compound is a substance which is formed by two or more different types of elements which are united chemically in a fixed proportion. All molecules are not compounds.

Good luck !
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Which of the following groups gets energy directly from an insect that it eats?
ASHA 777 [7]

C. Primary consumers

Explanation:

Producers are like grass, herbivore is like a cricket and primary consumers is like a bird

8 0
3 years ago
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5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure<br> water?
Margaret [11]

Answer:

\boxed {\boxed {\sf 2.8 \ m }}

Explanation:

The formula for molality is:

m=\frac{moles \ of \ solute}{kg \ of \ solvent}

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

moles= 0.210 \ mol \\kilograms = 0.075 \ kg

Substitute the values into the formula.

m= \frac{ 0.210 \ mol }{0.075 \ kg}

Divide.

m= 2.8 \ mol/kg= 2.8 \ m

The molality is <u>2.8 moles per kilogram</u>

5 0
2 years ago
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
2 years ago
When examining features on the ocean floor, like a volcano, how would it appear?
kogti [31]

The correct answer is 33% i tried it on a lesson.

8 0
3 years ago
A ballerina weighs 103 lbs and is up on her toes with only 10.0 cm2 of her slippers in contact with the floor. What pressure is
Ahat [919]

Answer:

A

Explanation:

1 lb = .453 kg...so...103 x .453 = 46.72 kg  

you then multiply that by the force of gravity which is 9.8(m/s2)...so...  

46.72 x 9.8 = 458 newtons(kg x m/s^2), which is the force.  

pressure (in pascals) = Force(N) / Area (m2)  

we need to convert 10cm2 to m2 which = .001m^2  

458 / .001 = 458000 = 4.58 x 10^5 Pa

8 0
3 years ago
Read 2 more answers
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