Question

. Leslie is blowing up one of her favorite photographs to hang on her wall. If the photo's original length and height were 8 inches and 15 inches, and the new height is 4 feet, how many feet must the new picture be

Answer 1

Answer:

$L_2 = 2\frac{2}{15}\ ft$

Step-by-step explanation:

Given

Original

$Length(L_1) = 8\ in$

$Height (H_1) = 15\ in$

New

$Height (H_2) = 4\ ft$

Required

Determine the new length (L2)

Since the original photographs was blown up; the original and the new photographs would have the same ratio

i.e.

$Ratio = L_1 : H_1$

and

$Ratio = L_2 : H_2$

Equate both ratios

$L_1 : H_1 = L_2 : H_2$

Rewrite as fraction

$\frac{L_1}{H_1} = \frac{L_2}{H_2}$

Substitute values for L1, H1 and H2

$\frac{8}{15} = \frac{L_2}{4}$

Multiply both sides by 4

$4 * \frac{8}{15} = \frac{L_2}{4} * 4$

$4 * \frac{8}{15} = L_2$

$\frac{4 * 8}{15} = L_2$

$\frac{32}{15} = L_2$

$2\frac{2}{15} = L_2$

$L_2 = 2\frac{2}{15}\ ft$

The new length must be $2\frac{2}{15}\ ft$