The formula for the area of a trapezoid is:
A= (a+b)/2*h
A=150
h=10
b=14
a=?
So we need to solve for a. Let's plug in the values that we do know...
A= (a+b)/2*h
150=(a+14)/2*10
150=(a/2+14/2)*10
150=(a/2+7)*10
Divide both sides by 10
15=a/2+7
subtract 7 from both sides
8=a/2
multiply both sides by 2
16=a
The other base is 16
answer 40
Step-by-step explanation:
because you added all together to make one
You should know that:
(a+b)(a+b)(a+b)
=a(a+b)(a+b)+b(a+b)(a+b)
=a(a²+2ab+b²)+b(a²+2ab+b²)
=a³+2a²b+ab²+a²b+2ab²+b³
=a³+3a²b+3ab²+b³
-----------------
If a=5x and b=-4y
(5x+(-4y))³
=(5x-4y)³
=(5x)³+3(5x)²(-4y)+3(5x)(-4y)²+(-4y)³
=125x³+3(25x²)(-4y)+15x(16y²)-64y³
=125x³+75x²(-4y)+240xy²-64y³
=125x³-300x²y+240xy²-64y³
It’s just 5 you divide 9 into 45 and get a whole number of 5
