Allen has a photo that is 6in by 8in what will the dimension of the photo be if he scales it down by a factor of 1\2

1 answer:

6 0

A photo of 6 and 8 is scaled down to 1/2 the size
To find this, you multiply both by 1/2 or divide by 2
The new dimensions are 3 by 4
6 divided by 2=3
8 divided by 2=4

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Y= -2x+3 fill in the table using this function rule.

sp2606 [1]

Answer:

there is no table!

Step-by-step explanation:

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3 years ago

Solve algebraically. <br> 3x + y =3 <br> Y = 2x - 7

Annette [7]

<span>3x + y =3
Y = 2x - 7

substitute </span>Y = 2x - 7 into 3x + y =3
3x + y =3
3x +2x - 7 =3
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x = 2

Y = 2x - 7 = 2(2) - 7 = -3

answer
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Read 2 more answers

Solve sint = cos2t, for –4π ≤ t ≤ –2π

e-lub [12.9K]

Answer:

-(23/6)π

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Step-by-step explanation:

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sint=1-2sin^2t, if x=sint, thenn we have 2x^2+x-1=0

Here x=0.5, x=-1, as x=sint => sint = -1 solutions for -4π to -2π is t=-3π,

sint = 0.5 solutions for -4π to -2π is t= -(23/6)*π, and t = -(19/6)*π

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3/9 + 3/27 = ? Adding fractions

RideAnS [48]

$\frac{3}{9}$ + $\frac{3}{27}$ equals $\frac{4}{9}$ .

First, simplify $\frac{3}{9}$ to $\frac{1}{3}$ and also $\frac{3}{27}$ to $\frac{1}{9}$ . Your problem should look like: $\frac{1}{3}$ + $\frac{1}{9}$ .
Second, find the least common denominator of $\frac{1}{3}$ and $\frac{1}{9}$ to get 9.
Third, make the denominators the same as the least common denominator (LCD). Your problem should look like: $\frac{1x3}{3x3}$ + $\frac{1}{9}$ .
Fourth, simplify to get the denominators the same. Your problem should look like: $\frac{3}{9}$ + $\frac{1}{9}$ .
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m_a_m_a [10]

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