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exis [7]
3 years ago
5

Allen has a photo that is 6in by 8in what will the dimension of the photo be if he scales it down by a factor of 1\2

Mathematics
1 answer:
lesantik [10]3 years ago
6 0
A photo of 6 and 8 is scaled down to 1/2 the size
To find this, you multiply both by 1/2 or divide by 2
The new dimensions are 3 by 4
6 divided by 2=3
8 divided by 2=4
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What is the value of 4³÷ 2³ ?
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3 years ago
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Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an
Mashutka [201]

Answer:

\sqrt\frac{387}{20}

Step-by-step explanation:

Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx

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1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})

=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}

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Using T1-Calculator

=\sqrt\frac{387}{20}

3 0
3 years ago
A container manufacturer plans to make rectangular boxes whose bottom and top measure 2x by 3x. The container must contain 12in.
lisabon 2012 [21]

The height of the container be so as to minimize cost will be 1.20. inches.

<h3>How to calculate the height?</h3>

The volume of the box will be:

= 2x × 3x × h

= 6x²h

Volume = 6x²h

12 = 6x²h

h = 2x²

The cost function will be:

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C = 31.2x² + 51.6xh

Taking the derivative

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h = 1.20

Therefore, the height of the container be so as to minimize cost will be 1.20 inches.

Learn more about height on:

brainly.com/question/15557718

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