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ANEK [815]
3 years ago
6

You put steel wool in a water bottle and put a balloon on top. The balloon starts to expand. Which type of property are you test

ing?
Chemical--oxidation
Chemical-compound
Physical-oxidation
Physical-compound
Chemistry
2 answers:
monitta3 years ago
6 0
Physical-Oxidation so C is your answer
Irina18 [472]3 years ago
4 0
It’s c, physical to oxidation
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How Many Atoms are present in this formula NH4NO3
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2 nitrogen atoms, 4 hydrogen atoms and 3 oxygen atoms
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3 years ago
A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO
Akimi4 [234]

Answer: The empirical formula for the given compound is CH_2

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=22.0g

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, \frac{12}{44}\times 22.0=6g of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = \frac{0.5}{0.5}=1

For Hydrogen  = \frac{1.0}{0.5}=2

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is C_{1}H_{2}=CH_2

4 0
4 years ago
What volume is occupied by 26.6 g of argon gas at a pressure of 1.29 atm and a temperature of 355 K ?
agasfer [191]

Answer:

V = 15 L

Explanation:

PV = nRT

P = 1.29 atm, T= 355 K mass argon 40g/mol

n = mass/ molecular mass; n = 26.6 g/40 g/mol; n = 0.665 mol

V = (0,665 mol x 0.082 x 355 K) / 1.29 atm = 15 L

4 0
3 years ago
Which will have the lowest boiling point between pure water, 0.5NacI, 1.0 NaCi or 2.0 NaCi?
Andru [333]

Answer:

pure water will have the lowest boiling point.

3 0
3 years ago
What are the rules for naming hydrocarbons?
GrogVix [38]

Answer:

IUPAC Rules for Alkane Nomenclature

Find and name the longest continuous carbon chain.

Identify and name groups attached to this chain.

Number the chain consecutively, starting at the end nearest a substituent group.

Designate the location of each substituent group by an appropriate number and name.

Explanation:

3 0
3 years ago
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