If the solid, liquid, and gas forms of a substance

I need help on 3 and 4 please I'm very confused and can not answer these questions I'm in sixth grade and it's hard

OverLord2011 [107]

D. Wind will always move from areas of high pressure to low pressure. It's the reason we have weather, or one of them. Temperature is another factor.

B. That is the definition of the greenhouse effect.

4 0

3 years ago

Which element has the greatest density at STP?

son4ous [18]

Answer: Option (4) is the correct answer.

Explanation:

It is known that density is mass divided by volume.

Mathematically, Density = $\frac{mass}{volume}$

Since, density is directly proportional to mass. So, more is the mass of an element more will be its density.

Mass of magnesium is 24.305 g/mol.

Mass of barium is 137.327 g/mol.

Mass of beryllium is 9.012 g/mol

Mass of radium is 226 g/mol.

Hence, radium has more mass therefore it will have the greatest density at STP.

8 0

3 years ago

During the following chemical reaction, 46.3 grams of C3H6O react with 73.2 grams of O2

ra1l [238]

Answer:

a) O2 is the limiting reactant

b) 75.70 grams CO2 (theoretical yield)

c) There remains 12.81 grams of C3H6O

d) The actual yield CO2 is 34.29 grams

Explanation:

Step 1: Data given

Mass of C3H6O = 46.3 grams

Mass of O2 = 73.2 grams

Molar mass of C3H6O = 58.08 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

C3H6O + 4O2 → 3 CO2 + 3H2O

Step 3: Calculate moles C3H6O

Moles C3H6O = mass C3H6O / molar mass C3H6O

Moles C3H6O = 46.3 grams / 58.08 g/mol

Moles C3H6O = 0.793 moles

Step 4: Calculate moles O2

Moles O2 = 73.2 grams / 32 g/mol

Moles O2 = 2.29 moles

Step 5: Calculate limiting reactant

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed. (2.29 moles).

C3H6O is in excess. There will react 2.29/4 = 0.5725 moles C3H6O

There will remain 0.793 - 0.5725 = 0.2205 moles C3H6O

This is 0.2205 moles * 58.08 g/mol = 12.81 grams

Step 6: Calculate moles of CO2

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

For 2.29 moles O2 we need 3/4 * 2.29 = 1.72 moles CO2

This is 1,72 moles * 44.01 g/mol = 75.70 grams CO2

Step 7: Calculate actual yield

% yield = 45.3 % = 0.453 = (actual yield / theoretical yield)

actual yield = 0.453 * 75.70 = 34.29 grams

3 0

3 years ago

The chemical reaction that occurs in a gas grill is the combustion of propane, C3H8. Write a balanced equation for this reaction

Orlov [11]

C3H8 (liquid) + 5O2 (gas) ➡️ 3CO2 (gas) + 4H2O (liquid)

3 0

3 years ago

Read 2 more answers

Look up and compare the normal boiling points and normal melting points of H2O and H2S. Based on these physical properties, whic

NeTakaya

Explanation:

Both melting and boiling point of water are much higher that that of H2S.

The MP and BP of water are 0°C and 100°C respectively whereas the MP and BP of H2S are -82°C and -60°C respectively.

Clearly, the intermolecular forces in H2O are much stronger than in H2S because, H2O has hydrogen bonding in it, which is both inter and intra. Whereas H2S has only weak van der waal force between their molecules. This is why boiling and melting points of H2O is more than that of H2S.

Hydrogen bonding is a particular type of dipole-dipole association which occurs between atoms of hydrogen bound to strongly electronegative atoms that are either fluorine, oxygen or nitrogen.

The hydrogen atom's partially positive side is drawn to the partially negative end of these atoms found in some other molecule. It is a strong binding mechanism between the molecules.

7 0

3 years ago