Ask question

Ask question

All categories

2 years ago

14

Betsy was in a car accident. Her monthly insurance payment of $225 will now be increased by 25%. How much will her monthly payme

nt now be?
A. $56.25
B. $275
C. $281.25
D. $270

1 answer:

sleet_krkn [62]2 years ago

5 0

Answer:

281.25 that is the answer

You might be interested in

Find the axis of symmetry for the equation in vertex form. y=(x+2)^2+1

VikaD [51]

I’m not sure but use Desmond

6 0

3 years ago

Jonas wrote 9 + 8 equals 17 what number sentence shows the commutative property of addition

Tju [1.3M]

17=8+9. Communitive property is where you can rearrange everything.

5 0

3 years ago

Read 2 more answers

A study was conducted to estimate the difference in the mean salaries of elementary school teachers from two neighboring states.

umka21 [38]

Answer:

$(28900-30300) -2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = -3301.70$

$(28900-30300) +2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = 501.698$

The confidence interval would be $-3301.70 \leq \mu \leq 501.698$ and since the confidence interval contains the value of 0 we don't have enough evidence to conclude that the difference between the two states for the salary of teachers are significantly different.

Step-by-step explanation:

We have the following info given by the problem

$\bar X_1 = 28900$ the sample mean for the salaries of teachers in Indiana

$s_1 = 2300$ the sample deviation for the salary of teachers in Indiana

$n_1 =10$ the sample size from Indiana

$\bar X_2 = 30300$ the sample mean for the salaries of teachers in Michigan

$s_2 = 2100$ the sample deviation for the salary of teachers in Michigan

$n_2 =14$ the sample size from Michigan

We want to find a confidence interval for the difference in the two means and the formula for this case is given by;

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

The degrees of freedom for this case are:

$df = n_1 +n_2 -2= 10+14-2 =22$

The confidence is 95%so then the significance is $\alpha=0.05$ and the $\alpha/2 =0.025$ , we need to find a critical value in the t distribution with 22 degrees of freedom who accumulates 0.025 of the area on each tail and we got:

$t_{\alpha/2}= 2.07$

And now replacing in the formula for the confidence interval we got:

$(28900-30300) -2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = -3301.70$

$(28900-30300) +2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = 501.698$

The confidence interval would be $-3301.70 \leq \mu \leq 501.698$ and since the confidence interval contains the value of 0 we don't have enough evidence to conclude that the difference between the two states for the salary of teachers are significantly different.

6 0

2 years ago

Find x in this 45°-45°-90° triangle.<br><br> x =

Leokris [45]

Answer:

<u>x = 1.2√2</u>

Step-by-step explanation:

Taking the cosine value of the angle :

cos 45° = 1.2/x
1/√2 = 1.2/x
<u>x = 1.2√2</u>

4 0

2 years ago

Read 2 more answers

*HURRY PLEASE ANSWER* Richard is asked to spray wash the exterior of a building that is shaped like a cube. He decides to calcul

Ludmilka [50]

Answer:

D. He forgot to subtract the area of the base from the total surface area of the cube.

Step-by-step explanation:

He is only spray washing the *exterior* of the building; the base is not exposed so it will not be spray washed, which means Richard can use less water.

Hope this helps. :)

7 0

3 years ago

Read 2 more answers