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3 years ago

The law/principle that states that younger form over older layers is

Biology

1 answer:

Allisa [31]3 years ago

8 0

Answer:

The law of superposition

Explanation:

The law of superposition is an axiom and a basic principle of sedimentary stratigraphy, it explains that the layers of sediment are deposited in a temporal sequence, in which the oldest are in a lower position than the most recent. Therefore, if there has been no deformation, the lower layers were deposited before the ones above, so they are older.

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andreev551 [17]

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3 years ago

If you have an element with atomic no of 3 and 14 nuetrons how many what would be the atomic mass

pochemuha

I think this is answer but i'm not sure it is right or wrong 3+14= 17

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4 years ago

Joe is color blind. both his mother and his father have normal vision, but his mother's father (joe's maternal grandfather) is c

Arte-miy333 [17]

The answer is x-linked recessive. It is apparent that the color blindness affects the males hence it's caused by a sex-linked recessive gene. Males have XY homologous chromosomes. The X sister chromosome has more genes than the Y sister chromosome, hence most males are hemizygous for sex linked genes. This means that even recessive genes on the X chromosome are likely to be expressed in males.

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3 years ago

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Fantom [35]

Answer:

Electron

Explanation:

8 0

3 years ago

In a population of plants, the allele for long stems (S) is completely dominant over the allele for short stems (s). If 35% of t

Sergio [31]

Answer:

The correct answer would be 48 percent.

It can be solved by using the Hardy-Weinberg equation.

p² + 2pq+ q² = 1

p + q = 1

where, p² represents homozygous dominant's frequency that is, SS in this case,

q² represents homozygous recessive's frequency that is, ss in this case,

2pq represents heterozygous dominant's frequency that is, Ss in this case.

p represents dominant allele's frequency and q represents the recessive allele's frequency.

Now, the percentage of homozygous recessive or short stems is 35%. Therefore, the frequency of homozygous recessive would be 0.35.

Thus, the value of q² = 0.35

So, q = $\sqrt{0.35}$ = 0.59 which is approximately equals to 0.6.

As p + q = 1 so, q = 1 - 0.6 = 0.4

The frequency of heterozygous (Ss) = 2pq = 2(0.6)(0.4) = 0.48

Hence, the frequency of heterozygous would be 48 percent.

8 0

3 years ago