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3 years ago

What is the boundedness

Mathematics

1 answer:

DedPeter [7]3 years ago

8 0

Answer:

Boundedness requires that there is only a bounded number of different kinds of parts

Step-by-step explanation:

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Please help me because I am an incompetent small brain :0

sdas [7]

I’m pretty sure it is (7, 2)

7 0

3 years ago

What is 5 to the power of 1 in expanded form

fomenos

Answer:

5^1 in expended from is 5

hope it helps.

3 0

3 years ago

Boadu and ansah formed a company and agreed that their annual profit will be shared in the ratio of 4:5 respectively. If at the

lozanna [386]

Answer:

ghs 20,000

Step-by-step explanation:

If Boadu and ansah formed a company and agreed that their annual profit will be shared in the ratio of 4:5 respectively, the total ratio will be 4 + 5 = 9

Let Boadu share be x

Let ansah share be y

If at the end of the year ansah received ghs5,000 more than Boadu, then;

y = 5000 + x

Boadu share = 4/9 * (x+y)

x+y is the total amount shared

x = 4/9 * (x+y)

Substitute y = 5000 + x

9x = 4(x+y)

9x = 4x + 4y

9x - 4x = 4y

5x = 4y

5x = 4(5000+x)

5x = 20,000 + 4x

5x-4x = 20,000

x = 20,000

Hence Boadu share is ghs 20,000

3 0

3 years ago

− 96 , 48 , − 24 , 12 , − 6 . what is the ratio of the geometric sequece

snow_tiger [21]

Answer:

-1/2

Step-by-step explanation:

it has to be a negative number since

every other number is negative

its a fraction since the numbers are decreasing

96 divided by 48 is 2

so the number being multiplied or ration must be -1/2

7 0

2 years ago

A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe

dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that $n = 8$

Each student has a 95% chance of passing their class independent of the other students, which means that $p = 0.95$

This probability is P(X = 8). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634$

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that $n = 2$

0.6634 probability all students pass in a class, which means that $p = 0.6634$ .

This probability is P(X = 1). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466$

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0

3 years ago