Answer:
The average value of
over the interval
is
.
Step-by-step explanation:
Let suppose that function
is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of
over the interval
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)



The average value of
over the interval
is
.
All we really need to do here is to convert 2 cm to meters. There are 100 cm in 1 meter, so the appropriate cm to meters conversion factor is
1 meter
-----------
100 cm
Thus,
2 cm 1 m
-------- * ----------- = (1/50) m = 0.02 m or 2.0*10^(-2) m (answer)
1 100 cm
Answer:
2 x 2 x 2 x 3, so its E
Step-by-step explanation: