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sertanlavr [38]
3 years ago
10

Write the equation of the line in slope-intercept from:

Mathematics
1 answer:
emmasim [6.3K]3 years ago
4 0

Answer:

1. 4x - 5

2. -2x + 6

3. x + 3

4. 4/3x - 5

Step-by-step explanation:

I used a calculator and my math skills :)

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Pedro solves the quadratic equation x^2+6x –14 using the quadratic formula. In which step did Pedro make an error?
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Step-by-step explanation:

The error is in step 2. The square root cannot be distributed to a sum.

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8 0
4 years ago
Please help fast! I'm being timed. <br> What is the value of x?
Naddika [18.5K]

That's Intersecting Secants, and we get


EC × ED = EB × EA


(x+4)(x+4+1) = (x+1)(x+1+11)


(x+4)(x+5) = (x+1)(x+12)


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6 0
3 years ago
f(x) = 4x^2+2x+6 What is the value of the discriminant of f? How many distinct real number zeros does f have?
Sauron [17]

Answer:

The value of Discriminant of the function is -92

It has ZERO distinct real number zeros.

Step-by-step explanation:

Given:

f(x)=4x^{2} +2x+6

Which is a Quadratic Equation in the general form of

ax^{2}+bx+c=0

where a,b and c are constants.So on comparing the given equation with general form we get,

a=4\\b=2\\c=6

Formula for discriminant we have

Discriminant=b^{2}-4ac\\ =2^{2}-4(4)(6)\\ =4-96\\=-92

now for zeros  we have

x=\frac{-b+\sqrt{b^{2-4ac} } }{2a} \\or\\x=\frac{-b-\sqrt{b^{2-4ac} } }{2a} \\

on substituting these values we get

x=\frac{-2+\sqrt{-92} }{8}

or

x=\frac{-2-\sqrt{-92} }{8}

the term \sqrt{-92} is imaginary

hence the zeros are not real number

3 0
3 years ago
Read 2 more answers
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