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Oksana_A [137]
3 years ago
6

The numbers 1 to 5 are placed in a hat. What is the probability that you will pick the number 1 pm

Mathematics
1 answer:
lys-0071 [83]3 years ago
5 0
What grade are you in? Lord
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Favorite vine? giving brainliest <3
Naya [18.7K]

Answer:lOoK aT aLl ThEsE cHiCkEnS

Step-by-step explanation:

5 0
3 years ago
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Find the area of the shade regions. Give your answer as a completely simplify exact value in terms of pie(no approximation). a=
mr Goodwill [35]

Answer:

<u>125.6 in²</u>

Step-by-step explanation:

Area shaded :

  • 2 × Sector (72°)
  • 2 x πr² x θ/360
  • 2 x 3.14 x 100 x 72/360
  • 6.28 x 100 x 1/5
  • 20 x 6.28
  • <u>125.6 in²</u>
4 0
2 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
The number 6,253 rounded to the nearest hundred is —————
faust18 [17]

Answer:

6300

Step-by-step explanation:

253 is closer to 300 than to 200

6 0
3 years ago
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A large company made $6,439,583 last year . what in the value of the 9 in $6,439,583?
Mama L [17]

The value of 9 is 9,000 it’s in the  Thousands place

8 0
3 years ago
Read 2 more answers
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