Answer:
hello your question has some missing parts below is the missing part
Given below are the analysis of variance results from a Minitab display. Assume that you want to use a 0.05 significance level in testing the null hypothesis that the different samples come from populations with the same mean.
Identify the p-value.
Source DF SS MS F p
Factor 3 13.500 4.500 5.17 0.011
Error 16 13.925 0.870
Total 19 27.425
A) 0.011 B) 4.500 C) 5.17 D) 0.870
answer : p-value = 0.011 ( A )
Step-by-step explanation:
using this information
Source DF SS MS F P
Factor 3 13.500 4.500 5.17 0.011
Error 16 13.925 0.870
Total 19 27.425
significance level = 0.05
given that the significance level = 0.05
and
F statistics are given as : F = 5.17 , F critical = 3.25
hence the p-value = 0.011
from the analysis the p-value is less than the significance level is lower than the significance level
Answer:
5
Step-by-step explanation:
-6 and 11 could be re written as
11-6=5
Answer:
There will be 90 ways to reach Greenup from Charleston.
Step-by-step explanation:
<em>Option C: 90 is correct.</em>
Let's name all the ways and try to visualize the roads.
C = Charleston
M = Mattoon
T = Toledo
G = Greenup
Task = Charleston to Greenup. How many different ways to reach?
1 1
2 2 1
C 3 M 3 T 2 G
4 4 3
5 5
6
So, Refer to this above diagram.
If we Start from C then go to 1 and then go to M and then go to 1 and then go to T and then go to 1 and then go G.
If you notice, in this single possibility we have 3 ways: C to 1 to M, M to 1 to T, T to 1 to G.
It means we will have: 5 x 6 x 3 = 90 number of ways to reach greenup from Charleston.
Answer:
the second one
Step-by-step explanation:
i read the problem and answered it