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jeka57 [31]
3 years ago
6

What is (xy)7 in expanded form

Mathematics
1 answer:
Natali5045456 [20]3 years ago
3 0

Answer:

7xy

Step-by-step explanation:

multiply the outside of the brackets by the inside so it is 7xy

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Plzzzzz help will give brainliest to the right answer!! What is x?(pic down below)
Alekssandra [29.7K]

Answer: 5

Step-by-step explanation:

20 * 60 is 120 then divide it by 24

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For every 3 cups of peanuts there are 2 cups of chocolate

9/3 = 3 so 3*2 = 6

For 9 cups of peanuts there are 6 cups of choclate

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inessss [21]

Answer:

The  same (42 degrees)

Step-by-step explanation:

This is because the angles are congruent or the same.

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3 years ago
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How does your cosine graph change when including the d-value?
fredd [130]

Answer:

Changing value of "d" changes the vertical shift of the cosine graph.

Step-by-step explanation:

Question says to find about how does your cosine graph change when including the d-value.

General equation of cosine function can be given as:

y=a\cdot\cos\left(bx-c)\right)+d

In that formula, value of  "d" gives vertical shift.

So changing value of "d" changes the vertical shift of the cosine graph.

6 0
3 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
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