Given :
The focal length of a concave mirror is 18 cm.
To Find :
The radius of curvature of the concave mirror.
Solution :
We know,
Therefore, the radius of curvature of concave mirror is 36 cm.
Hence, this is the required solution.
Answer:
W = 9.93 10² N
Explanation:
To solve this exercise we must use the concept of density
ρ = m / V
the tabulated density of copper is rho = 8966 kg / m³
let's find the volume of the cylindrical tube
V = A L
V = π (R_ext ² - R_int ²) L
let's calculate
V = π (4² - 2²) 10⁻⁴ 3
V = 1.13 10⁻² m³
m = ρ V
m = 8966 1.13 10⁻²
m = 1.01 10² kg
the weight of the tube
W = mg
W = 1.01 10² 9.8
W = 9.93 10² N
Answer:
Mg will replace Ag in a compound
Explanation:
A single replacement reaction is driven by the position of ions on the activity series.
As a rule of thumb, the position of metal ions on the activity series determines their reactivity.
Metal ions that are above another are more reactive and they will displace those that are lower.
Generally, activity increases as we go up the group.
Mg ions are higher than Ag ions on the series so, Mg will displace Ag from a solution.
The toast at this setting will always be the same color because the toaster uses a compensating thermostat. Depending on the setting, the compensating thermostat will be used to regulate the heat settings at different amounts of time. In one setting, the compensating thermostat could go on for much longer than the other setting before shutting off.
Answer:
m=417.24 kg
Explanation:
Given Data
Initial mass of rocket M = 3600 Kg
Initial velocity of rocket vi = 2900 m/s
velocity of gas vg = 4300 m/s
Θ = 11° angle in degrees
To find
m = mass of gas
Solution
Let m = mass of gas
first to find Initial speed with angle given
So
Vi=vi×tanΘ...............tan angle
Vi= 2900m/s × tan (11°)
Vi=563.7 m/s
Now to find mass
m = (M ×vi ×tanΘ)/( vg + vi tanΘ)
put the values as we have already solve vi ×tanΘ
m = (3600 kg ×563.7m/s)/(4300 m/s + 563.7 m/s)
m=417.24 kg
