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DENIUS [597]
3 years ago
8

If the gravitational field strength at the top of Mount Everest is 9.772 N/kg, approximately how tall (in feet) is

Physics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

The height of the Everest mountain is, x =  8514.087 m

Explanation:

Given data,

The gravitational field strength at the top of mount Everest, gₓ = 9.772 m/s²

The formula for gravitational field strength is,

                               <em> gₓ = GM/(R+x)²</em>

Where, x is the height from the surface of the Earth

Therefore,

                                (R+x)² = GM/gₓ

                                     x = √(GM/gₓ) - R

Substituting the values,

                       x = √(6.67408 x 10⁻¹¹ X  5.972 x 10²⁴ / 9.772) - 6.378 x 10⁶

                       x =  8514.087 m          

Therefore, the height of the Everest mountain is, x =  8514.087 m                                                              

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An alternating current is set up in an LRC circuit.
Andreyy89

Answer:

(B) Resistor only

Explanation:

Alternating Current: These are currents that changes periodically with time.

An LRC  Ac circuit is an AC circuit that contains a Resistor, a capacitor and an inductor, connected in series.

In a purely resistive circuit, current and voltage are in phase.

In a purely capacitive circuit, the current leads  the voltage by π/2

In a purely inductive circuit, the current lags the voltage by π/2.

Therefore when a alternating current is set up in LRC circuit, in the resistor, the current and the voltage are in phase.

The right option is (B) Resistor only.

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3 years ago
If Vector A is (3, 0) and Vector B is (-3, 3), what is the resultant?
Archy [21]

Answer:resultant vector R = (0, 3)

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Vectors are added such that those in same directions are added together. The resultant vector R is the given by R = (3-3, 0+3)

= (0, 3)

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What is the radius of a communications satellite’s orbital path that is in a uniform circular orbit around Earth and has a perio
pantera1 [17]
If the period of a satellite is T=24 h = 86400 s that means it is in geostationary orbit around Earth. That means that the force of gravity Fg and the centripetal force Fcp are equal:

Fg=Fcp

m*g=m*(v²/R),
 
where m is mass, v is the velocity of the satelite and R is the height of the satellite and g=G*(M/r²), where G=6.67*10^-11 m³ kg⁻¹ s⁻², M is the mass of the Earth and r is the distance from the satellite. 

Masses cancel out and we have:

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r=G*(M/ω²r²),

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