3 years ago

Helps!! will give brainliest

Mathematics

1 answer:

JulijaS [17]3 years ago

6 0

a) the graphs of a equation are parallel

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3 years ago

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What is ∛1728. Then multiplied by ∛14903

NeTakaya

Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

<u>Solution: </u>

Need to calculate $\sqrt[3]{1728}$ and then multiply the result by $\sqrt[3]{14903}$

Let us first evaluate $\sqrt[3]{1728}$

$\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12$

As need to multiply 12 by $\sqrt[3]{14903}$

$\Rightarrow 12 \times \sqrt[3]{14903}$

On solving $\sqrt[3]{14903}$ , we get

$\sqrt[3]{14903}=24.608$

$\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306$

Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

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3 years ago

The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference.

dlinn [17]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=-5\\ n=10\\ a_{10}=13 \end{cases} \\\\\\ a_{10}=a_1+(10-1)d\implies 13=-5+(10-1)d \\\\\\ 13=-5+9d\implies 18=9d\implies \cfrac{18}{9}=d\implies \boxed{2=d}$