Answer:
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
Explanation:
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
Methane + oxygen → carbon dioxide + Water.
The balanced equation above shows the combustion of methane, CH4 in oxygen, O2 to yield carbon dioxide, CO2 and steam, H2O.
The mole ratio of combustion are as follows:
1 mole of CH4 burns in 2 moles of oxygen to produce 1 mole of CO2 and 2 moles of H2O and a lot of heat.
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<h3>
Answer:</h3>
0.643 moles
<h3>
Explanation:</h3>
We are given;
Density of nitrogen gas as 1.20 g/L
Volume nitrogen as 15.0 L
We are required to calculate the number moles of nitrogen gas;
<h3>Step 1: Determine the mass of nitrogen gas</h3>
We know the density is given by dividing mass by volume.
Therefore, to get the mass;
- Mass = Density × volume
- Mass = 1.20 g/L × 15.0 L
= 18 g
<h3>Step 2: Determine the mass of nitrogen gas </h3>
We know that to get the number of moles, we divide mass by molar mass;
That is, moles = Mass ÷ Molar mass
But, molar mass of nitrogen gas is 28 g/mol
Therefore;
Moles of nitrogen gas = 18 g ÷ 28 g/mol
= 0.643 moles
Therefore, the number of moles of nitrogen gas 0.643 moles
