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Olegator [25]
3 years ago
11

The chemical equation of photosynthesis includes 6O2. What does the small number after the O represent?

Chemistry
1 answer:
blondinia [14]3 years ago
3 0
Its the number of Oxygen molecules
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At 25°C and constant pressure, carbon monoxide gas combines with oxygen gas to give carbon dioxide gas with the evolution of 10.
stealth61 [152]

Answer : The value of \Delta H for the reaction is, -565.6 kJ

Explanation :

First we have to calculate the molar mass of CO.

Molar mass CO = Atomic mass of C + Atomic mass of O  = 12 + 16 = 28 g/mole

Now we have to calculate the moles of CO.

\text{Moles of }CO=\frac{\text{Mass of }CO}{\text{Molar mass of }CO}=\frac{1g}{28g/mole}=\frac{1}{28}mole

Now we have to calculate the value of \Delta H for the reaction.

The balanced equation will be,

2CO(g)+O_2(g)\rightarrow 2CO_2(g)

From the balanced chemical reaction we conclude that,

As, \frac{1}{28}mole of CO release heat = 10.1 kJ

So, 2 mole of CO release heat = 2\times 28\times 10.1=565.6kJ

Therefore, the value of \Delta H for the reaction is, -565.6 kJ (The negative sign indicates the amount of energy is released)

4 0
3 years ago
g If you have three identical containers (same volume) at the same temperature and pressure, each with a different gas. Containe
vekshin1

Answer:

<em>The three gases, in the three identical containers, will all have the same number of molecules</em>

Explanation:

If these three gases (Helium He, Neon Ne, and Oxygen O_{2}) are all contained in separate identical containers with the same volume. And they are all stored at the same temperature, and pressure. Then, they'll all contain the same number of molecules. This is in line with Avogadro's law which states that "Equal volume of all gases, at the same temperature and pressure, have the same number of molecules."

6 0
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Find [cu2+] in a solution saturated with cu4(oh)6(so4) if [oh − ] is fixed at 2.3 ✕ 10−6 m. note that cu4(oh)6(so4) gives 1 mol
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<span>

</span>Cu_4(OH)_6(SO_4)
<span>
You have OH-  conc = </span>2.3 ✕ 10−6 m
From the formula, you can observe the ratio of Cu2+ to OH- is  4 : 6 = 2:3

So, for 2.3 ✕ 10−6 m OH-
[Cu2+] = \frac{2}{3} \times 2.3 \times 10^{-6}

= 1.53  \times 10^{-6} &#10;

6 0
4 years ago
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