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nydimaria [60]
3 years ago
15

How would oxygen be represented in the formula equation for the reaction of methane and oxygen to yield carbon dioxide and water

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
6 0

Answer:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Explanation:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Methane + oxygen → carbon dioxide + Water.

The balanced equation above shows the combustion of methane, CH4 in oxygen, O2 to yield carbon dioxide, CO2 and steam, H2O.

The mole ratio of combustion are as follows:

1 mole of CH4 burns in 2 moles of oxygen to produce 1 mole of CO2 and 2 moles of H2O and a lot of heat.

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A certain substance melts at a temperature of . But if a sample of is prepared with of urea dissolved in it, the sample is found
pshichka [43]

Answer:

2.2 °C/m

Explanation:

It seems the question is incomplete. However, this problem has been found in a web search, with values as follow:

" A certain substance X melts at a temperature of -9.9 °C. But if a 350 g sample of X is prepared with 31.8 g of urea (CH₄N₂O) dissolved in it, the sample is found to have a melting point of -13.2°C instead. Calculate the molal freezing point depression constant of X. Round your answer to 2 significant digits. "

So we use the formula for <em>freezing point depression</em>:

  • ΔTf = Kf * m

In this case, ΔTf = 13.2 - 9.9 = 3.3°C

m is the molality (moles solute/kg solvent)

  • 350 g X ⇒ 350/1000 = 0.35 kg X
  • 31.8 g Urea ÷ 60 g/mol = 0.53 mol Urea

Molality = 0.53 / 0.35 = 1.51 m

So now we have all the required data to <u>solve for Kf</u>:

  • ΔTf = Kf * m
  • 3.3 °C = Kf * 1.51 m
  • Kf = 2.2 °C/m
5 0
3 years ago
_______ are prophylactic agents used to treat bronchoconstriction.
Brut [27]
Bronchodilators <span>are prophylactic agents used to treat bronchoconstriction.</span>
6 0
3 years ago
What is the eccentricity of mercury
suter [353]
According to my astronomy book, it's about 0.206
6 0
3 years ago
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What are the rules for writing chemical formulas
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6 0
3 years ago
How many moles of dinitrogen monoxide are present in 9.3 x 10^22 molecules of this compound?
Step2247 [10]

Answer:

<h2>0.15 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities.

From the question we have

n =  \frac{9.3 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.154485...

We have the final answer as

<h3>0.15 moles</h3>

Hope this helps you

8 0
3 years ago
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