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3 years ago

How would oxygen be represented in the formula equation for the reaction of methane and oxygen to yield carbon dioxide and water

Chemistry

1 answer:

Lera25 [3.4K]3 years ago

6 0

Answer:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Explanation:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Methane + oxygen → carbon dioxide + Water.

The balanced equation above shows the combustion of methane, CH4 in oxygen, O2 to yield carbon dioxide, CO2 and steam, H2O.

The mole ratio of combustion are as follows:

1 mole of CH4 burns in 2 moles of oxygen to produce 1 mole of CO2 and 2 moles of H2O and a lot of heat.

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From a cross between a short-haired guinea pig (hh) and a long-haired guinea pig (Hh), what would be the possible phenotypes of

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Answer:

Explanation:

There will be a two long hair and two short hair

5 0

3 years ago

Na CN + HCl ->?? <br><br>Thanks for your time

Tom [10]

Sodium chloride and prussic acid are formed

NaCN+HCl→NaCl+HCN

4 0

3 years ago

A 8.00 L tank at 26.9 C is filled with 5.53 g of dinitrogen difluoride gas and 17.3 g of sulfur hexafluoride gas. You can assume

pshichka [43]

Answer:

mole fraction of N_2 O = 0.330

mole of fraction SF_4 = 0.669

PRESSURE OF N_2 O = 39127.053 Pa

pressure of SF_4 = 792126.36

Total pressure = 118253.413 Pa

Explanation:

Given data:

volume of tank 8 L

Weight of dinitrogen difluoride gas 5.53 g

weight of sulphur hexafluoride gas 17.3 g

Amount of $N_2 O = \frac{5.53}{14*2 + 16} = 0.1256 mol$

amount of $SF_4 = \frac{17.3}{32.1 + 19*4} = 0.254 mol$

mole fraction of $N_2 O = \frac{0.1256}{0.1256 + 0.254} = 0.330$

mole of fraction $SF_4 = \frac{0.254}{0.1256 + 0.254} = 0.669$

PV = nRT

P of N_2 O $= \frac{0.1256 *8.31 (273 + 26.9}{0.008} = 39127.053 Pa$

mole of SF_4 $=\frac{0.254 *8.31*(273+26.9)}{.008} = 79126.36 Pa$

Total pressure = 39127.053 + 79126.36 = 118253.413 Pa

6 0

3 years ago

Which of the following factors does not affect a reaction rate?

Natalka [10]

The correct answer is C

4 0

3 years ago

A student is doing an experiment to determine the effects of temperature on an object. He writes down that the initial temperatu

bogdanovich [222]

Answer:

1) The Kelvin temperature cannot be negative

2) The Kelvin degree is written as K, not ºK

Explanation:

The temperature of an object can be written using different temperature scales.

The two most important scales are:

- Celsius scale: the Celsius degree is indicated with ºC. It is based on the freezing point of water (placed at 0ºC) and the boiling point of water (100ºC).

- Kelvin scale: the Kelvin is indicated with K. it is based on the concept of "absolute zero" temperature, which is the temperature at which matter stops moving, and it is placed at zero Kelvin (0 K), so this scale cannot have negative temperatures, since 0 K is the lowest possible temperature.

The expression to convert from Celsius degrees to Kelvin is:

$T(K)=T(^{\circ}C)+273.15$

Therefore in this problem, since the student reported a temperature of -3.5 ºK, the errors done are:

1) The Kelvin temperature cannot be negative

2) The Kelvin degree is written as K, not ºK

6 0

4 years ago