Answer:
2 HI(aq) + Ba²⁺(aq) + 2 OH⁻(aq) → 2 H₂O(l) + Ba²⁺(aq) + 2I⁻(aq)
Explanation:
Let's consider the following balanced molecular equation.
2 HI(aq) + Ba(OH)₂(aq) → 2 H₂O(l) + BaI₂(aq)
In the complete ionic equation we include all the ions and the species that do not dissociate in water. HI is a weak electrolyte so it exists mostly in the molecular form. H₂O has a very low equilibrium constant (Kw = 10⁻¹⁴) si it exists mainly in the molecular form.
2 HI(aq) + Ba²⁺(aq) + 2 OH⁻(aq) → 2 H₂O(l) + Ba²⁺(aq) + 2I⁻(aq)
Answer:
Benzaldehyde is less electrophilic than acetaldehyde
Explanation:
Electrophilicity of carbonyl carbon depends on it's positive charge density.
In benzaldehyde, phenyl group can act as an electron donating group towards carbonyl group due to it's electron donating resonating effect.
In acetaldehyde, methyl group can act as an electron donating group towards carbonyl group due to it's electron donating inductive effect.
We know that resonating effect are more stronger than inductive effect.
Henece, it is expected that positive charge density on carbonyl carbon is much lower in benzaldehyde than acetaldehyde.
So, benzaldehyde is less electrophilic than acetaldehyde.
Resonating effect of phenyl group has been shown below.
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You're going to divide the mass of chlorine within the compound by the mass of the compound, and then multiply the result by 100 to get the answer