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<h3><em /></h3><h3><u><em>The answer to this question is</em></u>: D) Generating electricity from a solar panel system.</h3><h3 />
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Answer:
The answers to the questions are;
Part A, endothermic
Part B, above 100 °C
Part C below 100 °C
Part D, 100 °C.
Explanation:
Part A endothermic,
The vaporization of water requires the addition of the heat of vaporization for the given mass of water as well as the heat required to raise the water to the boiling point.
Part B, above 100 °C
The boiling or vaporization of water is a spontaneous process above the boiling point for water which is 100 °C point
Part C below 100 °C
It is a non-spontaneous process below the boiling point of water which is 100 °C
Part D, 100 °C
Water is in equilibrium with steam at 100 °C.
Answer:
subtract the answer it'll get you that.
Explanation:
Answer:
Yes, yield.
Explanation:
N2(g) + 3 H2(g) → 2 NH3 (g) balanced equation
First, find limiting reactant:
Moles H2 = 1.83 g x 1 mole/2 g = 0.915 moles H2
Moles N2 = 9.84 g N2 x 1 mole/28 g = 0.351 moles N2
The mole ratio of H2: N2 is 3:1, so H2 is limiting (0.915 is less than 3 x 0.351)
Theoretical yield of NH3 = 0.915 mol H2 x 2 mol NH3/3 mol H2 = 0.61 moles NH3
Its phosphorus (P)In writing the electron configuration for Phosphorus the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for Phosphorous go in the 2s orbital. The next six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s. Since the 3s if now full we'll move to the 3p where we'll place the remaining three electrons. Therefore the Phosphorus electron configuration will be 1s22s22p63s23p3.