Answer:
40% of the ammonia will take 4.97x10^-5 s to react.
Explanation:
The rate is equal to:
R = k*[NH3]*[HOCl] = 5.1x10^6 * [NH3] * 2x10^-3 = 10200 s^-1 * [NH3]
R = k´ * [NH3]
k´ = 10200 s^-1
Because k´ is the psuedo first-order rate constant, we have the following:
b/(b-x) = 100/(100-40) ; 40% ammonia reacts
b/(b-x) = 1.67
log(b/(b-x)) = log(1.67)
log(b/(b-x)) = 0.22
the time will equal to:
t = (2.303/k) * log(b/(b-x)) = (2.303/10200) * (0.22) = 4.97x10^-5 s
Two distinct products of the reaction could emerge, both of which might turn out to be stereoisomers of one another.
<h3>What is the number of products?</h3>
We now understand that the chemical as demonstrated can experience monobromination, and the resulting compound is the same compound. However, due to the reaction's nature, we would have two steroisomers.
Given the reaction's process, we are aware that there are two distinct reaction products that may turn out to be stereoisomers of one another.
To learn more about stereochemistry visit:
brainly.com/question/13266152
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For every 3 Fe there is only 1 Fe3O4 producing.
So, ratio would be: Fe3O4 / Fe = 1 / 3
In short, Your Answer would be: 1 : 3
Hope this helps!
