The mass of carbon dioxide that would be needed to weigh is 462 grams.
Given:
10.5 moles of carbon dioxide.
The periodic table
To find:
The mass of carbon dioxide would be needed to weigh out to make 10.5 moles of carbon dioxide.
Solution:
Mass of carbon dioxide needed = m
Moles of carbon dioxide needed = 10.5 mol
The molar mass of carbon dioxide = M
The atomic mass of carbon atom = 12.011 g/mol
The atomic mass of oxygen atom = 15.999 g/mol
The moles of carbon dioxide will be given as:
The mass of carbon dioxide that would be needed to weigh is 462 grams.
Learn more about the moles of substance here:
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Answer: A reversible reaction is a reaction that takes place in back and front directions. If the reaction were to reach equilibrium, the rate of forward direction would be equal to that of the reverse reaction.
Explanation:
Reversible reactions :
These are the reaction in which reactants reacts to give product and products reacts to give reactants as a product in return.
- In above equation, 'A' and 'B' are reacting together to give 'C' and 'D', as products and vice-versa.
- When the above reaction reaches equilibrium the rate of forward and backward reaction becomes equal.
First, let's explain the variables. F means force, m means mass, and a means acceleration. F is measured in Newotns [N], mass is measured in kilograms [kg], and acceleration in measured in meters per squared second [m/s²].
Now let's mover on the first problem.
Given
m = 1000 kg
a = 3 m/s²
According to the second law of Newton, the force is equal to the acceleration multiplied by the mass.
The answer is 3000 N.
The second problem is smiliar.
Given
m = 70 kg
F = 250 N
We use the same formula from before, and use a bit of algebra to adapat it to our needs.
The answer is 24 1/7 s/m^2.
