It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
you have to use the formula
Step-by-step explanation:
length times with time height
There are 2 solutions. the highest degree of a polynomial is 2
Answer:
Try this: (2,6)
x=2, y=6
Step-by-step explanation:
Answer:
The answer to your question is b = 8.06 cm
Step-by-step explanation:
Data
hypotenuse = c = 9 cm
long leg = b = ?
short leg = a = 4 cm
Process
This is a right triangle so we must use the Pythagorean theorem to find the length of the long leg (b)
c² = a² + b²
-Solve for b²
b² = c² - a²
-Substitution
b² = 9² - 4²
-Simplification
b² = 81 - 16
b² = 65
-Result
b = 8.06 cm
