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Tatiana [17]
3 years ago
12

Maeve’s family recipe for macaroni and cheese makes 4 servings of 310 calories each. Maeve decided to make 1 1/2 times the amoun

t in the recipe. How many calories are in Maeve’s batch of macaroni and cheese?
Mathematics
1 answer:
ser-zykov [4K]3 years ago
5 0

Answer:

1,860 calories

Step-by-step explanation:

You start with 4 servings of macaroni and cheese with 310 calories per serving. She made 1 1/2 times more of the 4 servings. 1 1/2 as a decimal is 1.5, and 1.5 times 4 is 6. With 310 calories per serving you get the problem 6 x 310 which equals 1,860. Therefore, there are 1,860 calories in Maeve's mac n' cheese

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If an object is dropped from a height of 116, the function h(t)=-16t^2+116 gives the height of the object after t seconds. When
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Answer:

A

Step-by-step explanation:

To find how long it takes for the object to hit the ground you need to set h(t)=0 after this you need to find the number that when plugged into t makes the equation equal to 0

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2 years ago
How do I solve 6/2 + 8/3
Xelga [282]

Answer:

The solved given fractional expression is \frac{17}{3}

Therefore the given fractional expression becomes

\frac{6}{2}+\frac{8}{3}=\frac{17}{3}

Step-by-step explanation:

Given fractional expression  is  \frac{6}{2}+\frac{8}{3}

To solve the given fractional expression as below :

\frac{6}{2}+\frac{8}{3}

=3+\frac{8}{3}

 =\frac{3\times 3+8}{3}

( here taking the term 3 as LCM )

=\frac{9+8}{3}  ( by adding the sums here )

=\frac{17}{3}

\frac{6}{2}+\frac{8}{3}=\frac{17}{3}

Therefore the solved  given fractional expression  is  \frac{17}{3}

Therefore the  given  fractional  expression becomes  

\frac{6}{2}+\frac{8}{3}=\frac{17}{3}

The solved  given fractional expression  is  \frac{6}{2}+\frac{8}{3}=\frac{17}{3}

7 0
2 years ago
9 + 10 = 21 PLSSSSSSSSSSSSS
stellarik [79]

Answer:

9 + 10 +x= 21

x=21-19

x=2

add 2 in left hand side to get 21

6 0
3 years ago
Read 2 more answers
How do I solve 24(x-1) = -6(4-x)+18
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(x-4)/5=9-(2x-41)/9
jok3333 [9.3K]
For this question, you have to take Least Common Multiplier for which in this case will be "45" as, the denominators can get similar and get multiplied by a same value to form a similar expression. This allows us to cancel out them by common factors. Full process shown below.

\mathbf{Given \: \: Expression: \: \dfrac{x - 4}{5} = 9 - \dfrac{2x - 41}{9}}

\mathbf{\dfrac{x - 4}{5} \times 45 = 9 \times 45 - \dfrac{2x - 41}{9} \times 45}

\mathbf{9(x - 4) = 405 - 5 (2x - 41)}

\mathbf{9x - 36 = 405 - 10x + 205}

\mathbf{9x - 36 = - 10x + 610}

\mathbf{9x - 36 + 36 = - 10x + 610 + 36}

\mathbf{9x = - 10x + 646}

\mathbf{9x + 10x = - 10x + 646 + 10x}

\mathbf{19x = 646}

\mathbf{\dfrac{19x}{19} = \dfrac{646}{19}}

\mathbf{\therefore \quad x = 34}

\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is; \: \: x = 34}}}

Hope it helps.
3 0
2 years ago
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