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Rzqust [24]
3 years ago
13

Find each angle measure in the triangle. 3x° 2xº 4xº

Mathematics
2 answers:
Minchanka [31]3 years ago
7 0

The total measure of angles in a triangle is 180°.

3x° + 2x° + 4x° = 180°

9x° = 180°

x° = 180° ÷ 9

x° = 20

Our 3 angles are:

3(20) = 60°

2(20) = 40°

4(20) = 80°

Done.

yarga [219]3 years ago
6 0

Answer:

Step-by-step explanation:

3x+2x+4x=180

9x=180

x=180/9=20

3x=3×20=60°

2x=2×20=40°

4x=4×20=80°

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Suppose the roots of the equation 2x^2−5x−6=0 are α and β.Find the quadratic equation with roots 1/α and 1/β.​
pochemuha

Answer:

6x² + 5x - 2 = 0

Step-by-step explanation:

Given

2x² - 5x - 6 = 0 ← in standard form

with a = 2, b = - 5, c = - 6, then

sum of roots α + β = - \frac{b}{a} = \frac{5}{2}

product of roots = \frac{c}{a} = - 3, then

sum of new roots = \frac{1}{\alpha } + \frac{1}{\beta }

= \frac{\beta+\alpha  }{\alpha \beta }

= \frac{\frac{5}{2} }{-3} = - \frac{5}{6}

product of new roots = \frac{1}{\alpha } × \frac{1}{\beta }

= \frac{1}{\alpha\beta  } = - \frac{1}{3}

Hence the required equation is

x² + \frac{5}{6} x - \frac{1}{3} = 0 or

6x² + 5x - 2 = 0 ( multiplying through by 6 )

                           

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