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cestrela7 [59]
2 years ago
8

if a cell phone provider offers a plan that costs $20 per month plus $0.10 text messages sent or received a comparable plan cost

s $50 per month but offers unlimited text messaging how many text messages would have to be sent or received in order for the plans to cost the same each month
Mathematics
1 answer:
ruslelena [56]2 years ago
4 0

Answer: You would have to send 300 text messages

Step-by-step explanation:

1. Turn problem into 20 + 0.10x = 50

2. Subtract 20 from both sides to get 0.10x = 30

3. Divide both sides by 0.10 to get x = 300

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Simplify 8 - (-5) - 4(-7).
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Answer:41

Step-by-step explanation:

8 - (-5) - 4(-7) = 8+5+4*7=13+28=41

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3 years ago
In algebra, why do you think that you are given many problems to solve that aren't really "real life" problems? For example, "Tw
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Ummm because it makes you smarter???? I feel like this is a question to ask your teacher haha

Step-by-step explanation:

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3 years ago
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6. The height of a triangle is 2 units more than the base. The area of the triangle is 10 square units. Find
Harrizon [31]

Answer:

4.24

Step-by-step explanation:

First, let's set up the equation: \frac{2+x^2}{2}=10

Next, clear the fraction by multiplying both sides by 2:2*(\frac{2+x^2}{2}=10)=2+x^2=20

Then, subtract 2 from both sides: x^2=18

Finally, take a square root of both sides and round: \sqrt{x^2=18} =(Rounded to the nearest hundredth) 4.24

7 0
2 years ago
Point One = (-1,-1)<br> Point Two = (0,4)<br> Point-Slope Form:
-Dominant- [34]

Answer:

y+2=m(x+2)

Step-by-step explanation:

y - y1 = m(x - x1)

y- (-1) = m( x-(-1) )

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4 0
3 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulbs. The
faltersainse [42]

Answer:

34%

Step-by-step explanation:

Given that the distribution of daily light bulb request replacement is approximately bell shaped with ;

Mean , μ = 45 ; standard deviation, σ = 3

Using the empirical formula where ;

68% of the distribution is within 1 standard deviation from the mean ;

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Lightbulb replacement numbering between ;

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Number of standard deviations from the mean /

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(x - μ) / σ < Z < (x - μ) / σ

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This lies between - 1 standard deviation a d the mean :

Hence, the approximate percentage is : 68% / 2 = 34%

5 0
3 years ago
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