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2 years ago

9) A cow is tethered with a rope 20 ft long. What is the maximum area the cow can graze?

Mathematics

1 answer:

jenyasd209 [6]2 years ago

8 0

Answer:

If the rope is 20 ft long, then the maximum area the cow can graze is:

$\pi \\$ r^2 square feet.

$\pi$ is approximately 3.14, so that means we have: 3.14(20^2) = 1256 ft squared.

Thus, the maximum area that the cow can graze is 1256 ft squared.

Let me know if this helps!

You might be interested in

In Problems 1-8, determine the level of measurement of each variable.

lbvjy [14]

The level of measurement of each given variable are:

1. Ordinal

2. Nominal

3. Ratio

4. Interval

5. Ordinal

6. Nominal

7. Ratio

8. Interval

Level of measurement is used in assigning measurement to variables depending on their attributes.

There are basically four (4) levels of measurement (see image in the attachment):

1. Nominal: Here, values are assigned to variables just for naming and identification sake. It is also used for categorization.

Examples of variables that fall under the measurement are: Favorite movie, Eye Color.

2. Ordinal: This level of measurement show difference between variables and the direction of the difference. In order words, it shows magnitude or rank among variables.

Examples of such variables that fall under this are: highest degree conferred, birth order among siblings in a family.

3. Interval Scale: this third level of measurement shows magnitude, a known equal difference between variables can be ascertain. However, this type of measurement has no true zero point.

Examples of the variables that fall here include: Monthly temperatures, year of birth of college students

4. Ratio Scale: This scale of measurement has a "true zero". It also has every property of the interval scale.

Examples are: ages of children, volume of water used.

Therefore, the level of measurement of each given variable are:

1. Ordinal

2. Nominal

3. Ratio

4. Interval

5. Ordinal

6. Nominal

7. Ratio

8. Interval

Learn more about level of measurement here:

brainly.com/question/20816026

3 0

2 years ago

I need help please someone help

schepotkina [342]

Answer:

It's the second box.

Step-by-step explanation:

There, you are getting the most product for the cheapest.

4 0

3 years ago

Given that f(x) = 7x^2 − 84 = 0, find x.

jasenka [17]

Answer:

x = 3.464

Step-by-step explanation:

7x^2 - 84 = 0

7x^2 = 84

x^2 = 12

x= 3.464

8 0

3 years ago

The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in

Stolb23 [73]

Answer:

$ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75$

±0.75 ounce

Step-by-step explanation:

Assuming this complete question: The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in that state. To do this, they have selected a random sample of 300 people from the designated population. The following results were recorded: xbar=34.5 ounces, s=7.9 ounces Given this information, if the leaders wish to estimate the mean milk consumption with 90 percent confidence, what is the approximate margin of error in the estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=34.5$ represent the sample mean

$\mu$ population mean (variable of interest)

s=7.9 represent the sample standard deviation

n=300 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=300-1=299$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,199)".And we see that $t_{\alpha/2}=1.653$