Answer:
A.) 34.866 x 10¯23 g/atom
B.) 2.64 x 10^22 atoms in 1 cm3
C.) 1 atoms per unit cell
Explanation:
A) Calculate the average mass of one atom of polonium:
210g mol¯1 ÷ 6.022 x 1023 atoms mol¯1 = 34.866 x 10¯23 g/atom
B) Determine atoms in 1 cm3:
9.19g / 34.866x 10¯23 g/atom = 2.64 x 10^22 atoms in 1 cm3
Determine volume of the unit cell:
(3.37 x 10¯8 cm)3 = 3.827 x 10¯23 cm3
Determine number of unit cells in 1 cm3:
1 cm3 / 3.827 x 10¯23 cm3 = 2.61 x 1022 unit cells
C) Determine atoms per unit cell:
2.64 x 1022 atoms / 2.61 x 1022 unit cells = 1 atoms per unit cell
Answer:
The molecular weight of the unknown compound is 267.7 g/mol
Explanation:
Lowering vapor pressure → Colligative property where the vapor pressure of solution is lower than vapor pressure of pure solvent
ΔP = P° . Xm
0.526 atm - 0.501 atm = 0.025atm
0.025 atm = 0.526 atm . Xm
Xm = 0.025 atm / 0.526 atm → 0.0475 (mole fraction)
Mole fraction = Moles of solute / Total moles (solute + solvent)
0.0475 = Moles of solute / Moles of solute + Moles of solvent
We determine the moles of solvent → 116.2 g . 1mol / 58 g = 2 moles
0.0475 = Moles of solute / Moles of solute + 2
0.0475 moles of solute + 0.095 = Moles of solute
0.095 = Moles of solute - 0.0475 moles of solute
0.095 / 0.9525 = Moles of solute → 0.0997 moles
Molas mass = g/mol → 26.7 g / 0.0997 mol = 267.7 g/mol
Answer:
no equivale a nada porque
El vinagre suele contener ácido acético en una proporción de entre el 4% y 7%. Mucho más que un aderezo, el vinagre puede ser un eficaz y económico ayudante doméstico. Este popular producto, que recibe su nombre del latín vinum acre, es decir "vino agrio", y es básicamente ácido acético diluido.
Explanation:
espero y te sirva
The answer to this question is bohr Greek
Answer:
<h2>5.35 </h2>
Explanation:
The pH of a solution can be found by using the formula
![pH = - log [ {H}^{+} ]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5B%20%7BH%7D%5E%7B%2B%7D%20%5D)
We have
We have the final answer as
<h3>5.35 </h3>
Hope this helps you
