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3 years ago

When body temperature rises during physical activity, which thermoregulatory response is stimulated?

Chemistry

1 answer:

navik [9.2K]3 years ago

8 0

Answer: Heat dissipation mechanism

Explanation: Heat dissipation mechanism is a thermoregulatory response in humans whereby the hypothalamus of the brain initiates certain processes to reduce the high body temperature. Eg, sweating is initiated which helps cool down the body temperature, also superficial arteries are dilated, thereby leading to flushing and decreasing heatloss into the air. And metabolic heat production is also reduced.

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What were the reslt of aurangzeb's religion policy ? what measures did he takes

soldier1979 [14.2K]

Answer: The religious fanaticism of Aurangzeb overshadowed his virtues. His reversal of Akbar's policy of religious toleration resulted in weakening the entire structure of the Mughal empire. It led to several conflicts and wars in different parts of the country.

5 0

3 years ago

What type of bond is is formed when electrons move permanently from one atom to another upon reaction?

VLD [36.1K]

Ionic bonding would be the answer because they transfer electrons. This gives them a charge. If it loses electrons, it becomes an cation, with a positive charge. While if they gain an electron, they get a negative charge, and become a anion. Transferring an electron is losing or gaining, therefore your answer would be that since electrons are permanently being transferred, the answer is IONIC BOND.

Covalent bonds is a wrong answer because they share electrons, which gives them no charge (neutral).

Also, metallic bonding is not the correct answer.

So our final answer: A- Ionic bond

7 0

3 years ago

Read 2 more answers

Two samples of potassium iodide are decomposed into their constituent elements. The first sample produced 13.0g of potassium and

Leona [35]

Answer:

79.43kg

Explanation:

To adequately solve this problem, we should know the law of constant composition. This is a pointer to the fact that no matter the type of sample, the percentage compositions of potassium and iodine still remains the same. We can use these masses to get a formula and we would know the percentage compositions in whatever mass we are dealing with.

First of all, we add the masses in the first sample. 13 + 42.3 = 55.3

Hence, the percentage composition of the potassium is 13/55.3 * 100 = 23.51%

The percentage composition of the iodine is = 100 - 23.51 = 76.49%

Now, we need to get the formula of the compound. We can get this by dividing the percentage compositions with the atomic masses. The atomic mass of potassium and iodine is 39 and 127 respectively.

Potassium = 23.51/39 =0.603

Iodine = 76.49/127 = 0.602

We then divide by the smaller value to get the formula and this shoes our formula is KI

We can see they have a ratio of 1 to 1, meaning one atom of potassium to one atom of iodine. This further confirms the percentage compositions of 23.5 to 76.5

Now to get the mass of iodine yielded, let us say the mass is xkg

This means x/(x + 24.4) * 100 = 76.5

100x = 76.5( x + 24.4)

100x = 76.5x + 1866.6

100x - 76.5x = 1866.6

23.5x = 1866.6

x = 1866.6/23.5 = 79.43kg

4 0

3 years ago

Calculate the cell potential, the equilibrium constant, and the free energy change for

Tresset [83]

Answer:

Explanation:

Ba(s) + Mn²⁺ (aq,1M) → Ba²⁺ (aq,1M) + Mn(s)

Ba⁺²(aq) +2e → Ba(s) , E° = −2.90 V

Mn⁺²(aq) +2e → Mn(s), E⁰ =0.80 V

Anode reaction :

Ba(s) → Ba⁺²(aq) +2e E° = −2.90 V

Cathode reaction :

Mn⁺²(aq) +2e → Mn(s) E⁰ =0.80 V

Cell potential = Ecathode - Eanode

Ecell = .80 - ( - 2.90 )

Ecell = 3.7 V .

equilibrium constant ( K ) :

Ecell = .059 log K / n

n = 2

3.7 = .059 log K / 2

log K = 125.42

K = 2.63 x 10¹²⁵ .

Free energy change :

ΔG = - n F Ecell

= - 2 x 96500 x 3.7

= 714100 J

= 7.141 x 10⁵ J .

5 0

3 years ago

10 POINTS

lorasvet [3.4K]

De Broglie predicted that in his equation. The ball is not a particle.<span>
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5 0

3 years ago