6. You must divide the mass by it’s molar mass to give you the total amount of moles within that piece. This will give you approx 0.05mol. You can now multiply this value by Avagadros constant which gives you 2.93 x 10^22 atoms. I would expect gold to have less atoms as it’s molar mass is higher than that of silvers, meaning that less atoms would be required to equal the same mass
When the cell potential is positive then the electrochemical reaction is spontaneous. The Ecell is positive when Zn serves as cathode and Mg serves as anode hence the reaction is spontaneous.
An electrochemical cell is any type of cell in which energy is produced by a spontaneous chemical reaction. Redox reactions that occur in an electrochemical cell produce energy.
An electrochemical cell becomes spontaneous only when Ecell is positive. Ecell is positive when a metal that has a more negative electrode potential serves as the anode.
Since Mg has a more negative electrode potential that Zn, it follows that a cell in which Mg is the anode and Zn is the cathode will have a positive Ecell and the reaction will be spontaneous.
Learn more: brainly.com/question/857770
Answer:
<h3>the equilibrium constant of the decomposition of hydrogen bromide is 0.084</h3>
Explanation:
Amount of HBr dissociated
2HBr(g) ⇆ H2(g) + Br2(g)
Initial Changes 2.15 0 0 (mol)
- 0.789 + 0.395 + 0.395 (mol)
At equilibrium 1.361 0.395 0.395 (mole)
Concentration 1.361 / 1 0.395 / 1 0.395 / 1
at equilibrium (mole/L)
![K_c=\frac{[H_2][Br_2]}{[HBr]^2} \\\\=\frac{(0.395)(0.395)}{(1.361)^2} \\\\=\frac{0.156025}{1.852321} \\\\=0.084](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5BBr_2%5D%7D%7B%5BHBr%5D%5E2%7D%20%5C%5C%5C%5C%3D%5Cfrac%7B%280.395%29%280.395%29%7D%7B%281.361%29%5E2%7D%20%5C%5C%5C%5C%3D%5Cfrac%7B0.156025%7D%7B1.852321%7D%20%5C%5C%5C%5C%3D0.084)
<h3>Therefore, the equilibrium constant of the decomposition of hydrogen bromide is 0.084</h3>
Answer:
1 mole of potassium hydroxide, KOH
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
KOH + HCl —> KCl + H₂O
Considering the balanced equation above, we can see clearly that 1 mole of potassium hydroxide, KOH reacted with 1 mole of hydrochloric acid, HCl.
Therefore, we can conclude that at every given point, 1 mole of potassium hydroxide, KOH is required to react with 1 mole of hydrochloric acid, HCl.
