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rjkz [21]
3 years ago
5

Please help!! I am struggling on cross-sections

Mathematics
1 answer:
uranmaximum [27]3 years ago
7 0

Answer:

I don’t know the answer I just need some points to ask more questions !!! have a good day !!

Step-by-step explanation:

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2 years ago
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Over the interval [0,2pi), what are the solutions to cos(2x) = cos(x)? check all that apply​
kykrilka [37]

\cos(2x)  =  \cos(x)

Solution (1)

2x = x + 2k\pi

2x - x = 2k\pi

x = 2k\pi

for k=0 / for k=1 / for k=-1

x=0 / x=2π / x=-2π

acc / acc / rej

solution (2)

2x =  - x  + 2k\pi

2x + x = 2k\pi

3x = 2k\pi

x =  \frac{2k\pi}{3}

for k=0 / for k=1 / for k=-1

x=0 / x=2π/3 / x=-2π/3

acc / acc / rej

Note that i'm trying values of K which make the answer belong to our interval;

So our solution which i will represent as a set is;

S € {0,2π/3,2π}

6 0
2 years ago
If f(x) = 2x+4, which of the following is the inverse of f(x)?
creativ13 [48]

Answer:

{f}^{ - 1} (x)=  \frac{x}{2}  - 2

Step-by-step explanation:

The given function is

f(x) = 2x + 4Let

y = 2x + 4

Interchange x and y.

x = 2y + 4

Solve for y,

x - 4 = 2y

Divide both sides by 2

y =  \frac{x}{2}  - 2

Therefore;

{f}^{ - 1} (x)=  \frac{x}{2}  - 2

3 0
2 years ago
Will mark as brainliest please help.
alex41 [277]
The first one is the answer to the first question.

the second one is the answer to the second question



8 0
2 years ago
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ZX is perpendicular bisector of WY if WY=24 what is WX
bixtya [17]

Answer:

12

Step-by-step explanation:

6 0
3 years ago
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