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zysi [14]
3 years ago
7

Please help me i’ll give brainliest

Mathematics
1 answer:
liraira [26]3 years ago
6 0

Answer:

105 degrees

Step-by-step explanation:

You need to understand the properties of corresponding angles and supplementary angles.

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Image down below plz help
Mariana [72]

Answer:

44?

Step-by-step explanation:

I realy just have a feeling

8 0
3 years ago
A is the point with coordinates (3,8) b is the point with coordinates (x,13) the gradient of an is 2.5 .work out the value of x
Solnce55 [7]

Answer:

x = 5

Step-by-step explanation:

The formula for the gradient is given by:

m = (y2 - y1)/(x2 - x1), where two points (x1, y1) and (x2, y2) are given.

Thus if we have a gradient of 2.5 and two points (3, 8) and (x, 13), we can substitute this into the above formula for the gradient to get:

2.5 = (13 - 8)/(x - 3)

2.5(x - 3) = 5 (Multiply both sides by (x - 3))

x - 3 = 2 (Divide both sides by 2.5)

x = 5 (Add 3 to both sides)

Thus, the value of x is 5.

7 0
3 years ago
Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

7 0
3 years ago
Simplify<br><br>-5/7(-(1 1/3-3/4)+1/3 / 4
koban [17]

Answer:

=5/21L+ -5/84

Step-by-step explanation:

=-(5/7) (-(1L/3-3/4)+1/3/4)

=(-5/7)(-(1L/3-3/4))+(-5/7)(1/3/4)

=5/21L= -15/28+ -5/84

=5/21L=+ -25/42

7 0
3 years ago
Which value of I makes the equation 6 (0.52 – 1.5) + 20 =-9- (1 + 6) true? 0 - 14 O1 14​
Virty [35]
-1 you are correct about that answer
6 0
3 years ago
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