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Black_prince [1.1K]
3 years ago
14

Please help!!!

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
7 0

Answer:

Perimeter: 3/4

Area: 9/16

Step-by-step explanation:

The ratio of the perimeters is equal to the ratio of the sides so:

18/24 = 3/4

Ratio of Area = (Ratio of Sides)^2

(3/4)^2 = 9/16

I wasn't sure about the answer so I used Gauthmath

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Your latitude is 40.0 N. Which of the following would be the position of the NCP at this location?
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The answer is b 50.0 N

Step-by-step explanation:

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2 years ago
Identify whether or not the following relation represents direct variation: x/y = 6
vekshin1

Answer:

since the ratio of y to x (also written y:x) never changes. The number 6 in the equation yx=6 y x = 6 is called the constant of variation. The equation yx=6 y x = 6 can also be written in the equivalent form, y=6x y = 6 x .

Step-by-step explanation:

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2 years ago
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
Part A
rjkz [21]

Answer:

Step-by-step explanation:

Part A

Solve 4,500 ÷ 90. Enter your answer in the box.

 

Answer : 50

Part B

Select all the expressions that are equal to 4,500 ÷ 90.

A. 4,500 ÷ 9 tens  ✔️

B. 450 ÷ 90  ❌

C. 450 ÷ 9  ❌

D. 4,500 ÷ 9  ❌

E. 4,500 ÷ 90 tens ❌

8 0
3 years ago
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