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3 years ago

Determine the approximate value of a. 18.11 7.05 7.95 9.71

Mathematics

1 answer:

Alex777 [14]3 years ago

6 0

Answer:

7.95

Step-by-step explanation:

In order to solve this, we need to use the rule of sine which is (a/sinA)=(b/sinB)=(c/sinC). Since we have both values of c we can do (12/sin104), which equals ~12.37. Therefore, since we already have A, 12.37=(a/sin40). We can change this by doing sin40×12.37=a. sin40×12.37=7.95.

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Which angles are congruent to each other

katrin2010 [14]

Answer:

Step-by-step explanation:

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2 years ago

A store has 1173 pairs of socks. the socks are sold in packs of 4 pairs. how many packs of socks can the store sell?

Nadusha1986 [10]

Answer:

293 packs is the maximum the store can sell.

Step-by-step explanation:

Determine the number of packs that can be made with 4 pairs of socks.

(1173 pairs)/(4 pairs/pack) = 293.25 packs

We can't sell 0.25 pack (1 pair of socks), so drop that fraction to yield 293 full packs. Donate the spare pair, so to speak, to the local IRS agent.

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1 year ago

Find the indicated probability. round to three decimal places. a test consists of 10

Charra [1.4K]

To answer this problem, we use the binomial distribution formula for probability:

P (x) = [n! / (n-x)! x!] p^x q^(n-x)

Where,

n = the total number of test questions = 10

x = the total number of test questions to pass = >6

p = probability of success = 0.5

q = probability of failure = 0.5

Given the formula, let us calculate for the probabilities that the student will get at least 6 correct questions by guessing.

P (6) = [10! / (4)! 6!] (0.5)^6 0.5^(4) = 0.205078

P (7) = [10! / (3)! 7!] (0.5)^7 0.5^(3) = 0.117188

P (8) = [10! / (2)! 8!] (0.5)^8 0.5^(2) = 0.043945

P (9) = [10! / (1)! 9!] (0.5)^9 0.5^(1) = 0.009766

P (10) = [10! / (0)! 10!] (0.5)^10 0.5^(0) = 0.000977

Total Probability = 0.376953 = 0.38 = 38%

There is a 38% chance the student will pass.

7 0

3 years ago

Some people think it is unlucky if the 13th day of a month falls on a Friday. Show that in every calendar year (non leap or leap

MakcuM [25]

We will set a variable, d, to represent the day of the week that January starts on. For instance, if it started on Monday, d + 1 would be Tuesday, d + 2 would be Wednesday, etc. up to d + 6 to represent the last day of the week (in our example, Sunday). The next week would start over at d, and the month would continue. For non-leap years:
If January starts on d, February will start 31 days later. Following our pattern above, this will put it at d + 3 (28 days would be back at d; 29 would be d+1, 30 would be d+2, and 31 is at d+3). In a non-leap year, February has 28 days, so March will start at d+3 also. April will start 31 days after that, so that puts us at d+3+3=d+6. May starts 30 days after that, so d+6+2=d+8. However, since we only have 7 days in the week, this is actually back to d+1. June starts 31 days after that, so d+1+3=d+4. July starts 30 days after that, so d+4+2=d+6. August starts 31 days after that, so d+6+3=d+9, but again, we only have 7 days in our week, so this is d+2. September starts 31 days after that, so d+2+3=d+5. October starts 30 days after that, so d+5+2=d+7, which is just d. November starts 31 days after that, so d+3. December starts 30 days after that, so d+5. Remember that each one of these expressions represents a day of the week. Going back through the list (in numerical order, and listing duplicates), we have d, d, d+1, d+2, d+3, d+3, d+3, d+4, d+5, d+5, d+6 and d+6. This means we have every day of the week covered, therefore there is a Friday the 13th at least once a year (if every day of the week can begin a month, then every day of the week can happy for any number in the month).
For leap years, every month after February would change, so we have (in the order of the months) d, d+3, d+4, d, d+2, d+5, d, d+3, d+6, d+1, d+4, and d+6. We still have every day of the week represented, so there is a Friday the 13th at least once. Additionally, none of the days of the week appear more than 3 times, so there is never a year with more than 3 Friday the 13ths.

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3 years ago

Kyra see a pair of boots that costs $60.00.They are on salenfor 25% off.She also has a coupon for an additional 10% off.How much

nikitadnepr [17]

It's 40.5
$60 \times .25 \\ 45 \times .10$

4 0

3 years ago