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a_sh-v [17]
3 years ago
7

4. A function consists of the pairs (2,3), (x, y) and (5,6). If the inverse is also a function what values can y NOT be? Explain

.

Mathematics
1 answer:
Luba_88 [7]3 years ago
4 0

Answer:

In a nutshell, y cannot be 3 or 6 in the inverse function for all x distinct from 2 and 5.

Step-by-step explanation:

From Functional Theory we remember that a function is a relation in which all elements of its domain has an unique and different element from range. If y is the image of the inverse, which is a function, then y \neq 3, 6. Otherwise, the inverse could not be a function when x \in \mathbb{R}-\{2,5\}.

In a nutshell, y cannot be 3 or 6 in the inverse function for all x distinct from 2 and 5.

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Un granjero tiene 100 vacas que pesan 125 kg cada una. El costo diario de mantenimiento de una vaca asciende a $ 5.00. Las vacas
solniwko [45]

Answer:

25 days

Step-by-step explanation:

Assuming that the farmer waits for n days to get get the maximum profit.

Given that the total number of cows the farmer has, = 100

Currect weight of one cow = 125 kg.

Weight gain rate for one cow = 3 kg/day

So, weight gained by one cow in n days = 3n kg

Therefore, the weight of one cow after n days = 125 + 3n \;\;kg \cdots(i)

Cost for keeping one cow = $5/day.

Cost for keeping one cow for n days = $ 5n

So, Cost for keeping 100 cows for n days = \$ 5n \times 100 =\$500n \cdots(ii)

Current market price = 25 pesos / kg = 125 cents / kg [ as 1 peso = 5 cents]

The falling rate of market price = 1 cent /day.

Fall in price in n days = 1\times n = n cents.

So, market price after n days = 125-n cent/kg\cdots(iii)

By using equations (i) and (iii),

The selling price of one cow after n days = (125+3n) \times (125-n) cents.

So, the selling price of 100 cows after n days = (125+3n) \times (125-n)\times 100 cents.

As 1 $ = 100 cents. so

The selling price of 100 cows after n days =\$ 5(125+3n) (125-n)\cdots(iv).

Now, from equations (ii) and (iv)

Net profit, P = 5(125+3n) (125-n) - 500n\cdots(v)

To get the maximum profit, differentiate the profit function in equation (v) with respect to n and equate it to zero to get the value of n, i.e

\frac {dP}{dn}=0 \\\\\Rightarrow \frac {d}{dn}(5(125+3n) (125-n) - 500n)=0 \\\\\Rightarrow  5[ (125+3n)(-1)+(125-n)(3)]-500=0 \\\\\Rightarrow 5[ -125-3n+375-3n]-500 =0 \\\\\Rightarrow 5[ -125-3n+375-3n]=500\\\\\Rightarrow 250-6n=500/5=100 \\\\\Rightarrow 6n = 250-100=150 \\\\\Rightarrow n= 150/6 = 25.

Hence, the farmer has to wait for 25 days to get the maximum profit.

3 0
3 years ago
In the cafeteria, 100 milk cartons were put out for breakfast. After breakfast there were 40 milk cartons left. What is the rati
Assoli18 [71]

Answer:

1:4

Step-by-step explanation:

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3 years ago
What is the rate unit for 1700 meters in 40 minutes <br><br><br><br> please help
Rudik [331]

Answer:

42.5m/s

Step-by-step explanation:

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Which expression is equal to the length of the hypotenuse of a right triangle, formed inside the unit circle, with a radius of 1
Kitty [74]

Answer:

The length of the hypotenuse is equal to 2 units

Step-by-step explanation:

we know that

If the right triangle is formed inside the unit circle (inscribed triangle)

then

the hypotenuse of the right triangle must be equal to the diameter of the unit circle

we have

r=1 unit

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therefore

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Answer:

It is simplified

Step-by-step explanation:

13 cant go into any other number.

I hope this helps and have a great day! :)

8 0
3 years ago
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