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3 years ago

(75 points and brainliest for correct answer no explanation needed just answer.) NEED HELP

Mathematics

1 answer:

Alecsey [184]3 years ago

7 0

I believe that the answeres are either (The functions have the same shape. The Y intercept of y= |x| is 0, and the y-intercept of the second function is -9) or ( the two functions are the same) my best guess is (The functions have the same shape. The Y intercept of y= |x| is 0, and the y-intercept of the second function is -9)

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When 200 gallons of oil were removed from a tank, the volume of oil left in the tank was 3/7 of the tank's capacity. what was th

ki77a [65]

Answer:

Step-by-step explanation:

"When 200 gallons of oil were removed from a tank" algebraically looks like this:

V - 200.

"...the volume of oil left in the tank was 3/7 of the tank's capacity" algebraically looks like this:

3/7(V)

Therefore, the equation is

V - 200 = 3/7(V)

Begin by multiplying both sides by 7:

7(V - 200) = 3V and

7V - 1400 = 3V so

-1400 = -4V so

V = 350 gallons

That's if the volume of the oil in the tank was 3/7 of the tank's capacity.

For the other part of the problem, we set up the equation almost the same, except the 3/7 is a 1/2:

V - 200 = 1/2(V)

Multiplying both sides by 2 gives you

2(V - 200) = V and

2V - 400 = V so

-400 = -V so

V = 400

7 0

2 years ago

What angle corresponds to angle AFG?

viva [34]

Look at the image below :)

In case you didn't know, corresponding angles are equal to each other and are on the same side of the traversal

Therefore the answer is angle CGH

Hope this helped!

7 0

3 years ago

Read 2 more answers

Compare -3.6 and 1.2.

jasenka [17]

Answer:

-3.6 is a negative number compared to 1.2. 1.2 is -3 times less than -3.6. -3.6 is -3 times more than 1.2

Step-by-step explanation:

(can I get brainliest)

8 0

2 years ago

Read 2 more answers

A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t

Sati [7]

Answer:

$\frac{2}{7}$

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = $\frac{1}{7}$

Remaining fuel after driving around the city = 1 - $\frac{1}{7}$

= $\frac{7 - 1}{7} = \frac{6}{7}$

According to question:

As from the rest of the gas in the car that is $\frac{6}{7}$ , the car can complete 3 trip to Ottawa which means,

By unitary method:

The car can complete 3 trip by using = $\frac{6}{7}$ tank of gas.

The car can complete 1 trip by using = $\frac{6}{7} \div 3$

= $\frac{6}{7} \times\frac{1}{3}$

= $\frac{6}{21}$

= $\frac{2}{7}$ tank of gas

Thus, $\frac{2}{7}$ tank of gas used for each complete trip to Ottawa.

5 0

3 years ago

two trains leaves stations 320miles apart at the same time and travel toward eachother. One train travels at 110 miles per hour

I am Lyosha [343]

x/110 = (320-x)/90

<span> Cross multiply</span>

90x = 35200-110x

200x=35200

X = 35200/200 = 176 (distance traveled by train going 110 mph

176/110 = 1.6 hours = 1 hour and 36 minutes

Check: 110*1.6 = 176, 90*1.6 = 144

176+144 = 320

it will take 1.6 hours ( 1 hour 36 minutes) for the trains to meet

4 0

3 years ago