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2 years ago

Which quantity is proportional to 21/3

Mathematics

1 answer:

suter [353]2 years ago

7 0

Answer:

7/1 you can simplify the top and bottom by 3

Step-by-step explanation:

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The length of a rectangle is five times its width. if the perimeter of the rectangle is 96 yd , find its area.

elena-14-01-66 [18.8K]

Rectangle has 4 sides dived 96 by 4 and then from there you have to make length be bigger than width

3 0

3 years ago

Each of the following tables defines a relationship between an input x and an output y. Which of the relationship respresent fun

sveticcg [70]

Answer:

wat

Step-by-step explanation:

nose

6 0

3 years ago

One cubic meter of water weighs approximately 2200 pounds. There are 100 cm in one meter. If you have a box-shaped fish tank tha

Diano4ka-milaya [45]

Answer:

158.4 pounds

Step-by-step explanation:

first find the volume of the tank

$V = 30 \times 30 \times 80$

$V = 72000 cm^3$

to convert this to m^3 we know that 1m = 100cm

$V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}}{100\,\text{cm}}\right)^3$

$V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}^3}{100^3\,\text{cm}^3}\right)$

the cm^3 cancel out.

$V = \dfrac{72000}{100^3} m^3$

$V = 0.072\,m^3$

by simply converting the side-lengths to meters beforehand can give you this answer directly:

$V = 0.3 \times 0.3 \times 0.8 = 0.072 m^3$

it is given that 1 meter cube of water weighs about 2200 pounds.

$1\,m^3 = 2200 \,\text{lb}$

multiply both sides with 0.072 to find our answer:

$1\,m^3 \times 0.072 = 2200 \times 0.072 \,\text{lb}$

$0.072\,m^3 = 158.4 \,\text{lb}$

hence the weight of the water in the tank would be 158.4 pounds!

3 0

3 years ago

Solving simular triangles advanced

Reptile [31]

Answer:

x = 3/2

Step-by-step explanation:

We can use ratios to solve

6 6+x

-------- = -----------

4 5

Using cross products

6*5 = 4 * (6+x)

30 = 24 + 4x

Subtract 24 from each side

30 -24 = 24+4x-24

6 = 4x

Divide each side by 4

6/4 = 4x/4

3/2 = x

3 0

3 years ago

Read 2 more answers

If DF = 9x-39, find EF.

otez555 [7]

$DF=DE+EF\\\\DF=9x-39\\DE=47\\EF=3x+10\\\\\text{substitute}\\\\9x-39=47+3x+10\\9x-39=3x+57\ \ \ |-3x\\6x-39=57\ \ \ \ |+39\\6x=96\ \ \ \ |:6\\x=16\\\\\text{put the value of x to the expression}\ 3x+10\\\\EF=3(16)+10=48+10=58$

Answer: EF = 58

7 0

3 years ago