Answer:
42 units^2
Step-by-step explanation:
We can split this shape into a rectangle and 2 congruent triangles.
First, let's find the area of the rectangle:
A_s=l*w
A_s=7*4
A_s=28
Next, we find the area of one triangle, since both triangles are identical:
A_t=b*h/2
A_t=7*2/2
A_t=7
The area of the shape is:
A=A_s+2A_t
A=28+2*7
A=28+14
A=42
Remember that the equation of a circle is:
![(x - h)^{2} + (y - k)^{2} = r^{2}](https://tex.z-dn.net/?f=%28x%20-%20h%29%5E%7B2%7D%20%2B%20%28y%20-%20k%29%5E%7B2%7D%20%3D%20%20r%5E%7B2%7D%20)
Where (h, k) is the center and r is the radius.
We need to get the equation into that form, and find k.
![x^{2} - 6x + y^{2} - 10y = 56](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-%206x%20%2B%20%20y%5E%7B2%7D%20-%2010y%20%3D%2056)
Complete the square. We must do this for x² - 6x and y² - 10y separately.
x² - 6x
Divide -6 by 2 to get -3.
Square -3 to get 9. Add 9,
x² - 6x + 9
Because we've added 9 on one side of the equation, we have to remember to do the same on the other side.
![x^{2} - 6x + 9 + y^{2} - 10y = 65](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-%206x%20%2B%209%20%2B%20y%5E%7B2%7D%20-%2010y%20%3D%2065)
Now factor x² - 6x + 9 to get (x - 3)² and do the same thing with y² - 10y.
y² - 10y
Divide -10 by 2 to get -5.
Square -5 to get 25.
Add 25 on both sides.
![(x - 3)^{2}+ y^{2} - 10y + 25= 90](https://tex.z-dn.net/?f=%20%28x%20-%203%29%5E%7B2%7D%2B%20y%5E%7B2%7D%20-%2010y%20%2B%2025%3D%2090)
Factor y² - 10y + 25 to get (y - 5)²
![(x - 3)^{2}+ (y - 5)^{2} = 90](https://tex.z-dn.net/?f=%20%28x%20-%203%29%5E%7B2%7D%2B%20%28y%20-%205%29%5E%7B2%7D%20%3D%2090)
Now our equation is in the correct form. We can easily see that h is 3 and k is 5. (not negative because the original equation has -h and -k so you must multiply -1 to it)
Since (h, k) represents the center, (3, 5) is the center and 5 is the y-coordinate of the center.
What is 4th to the 60th piwer
Answer:
median- 58.5
first quartile- 56
third quartile- 65
interquartile range- 9
Step-by-step explanation:
median is when you put the numbers from least to greated and find the middle number; so, you will put this set in that order= 38, 46, 55,56,58,59,61,65,67,75. now, you get stuck between 58 and 59. so you add them and divide by two to get 58.5. thats the median. The first quartile is any number from the set that is smaller than the median, basically the first half of it. now you will just find the median of that which is 56. that is your first quartile. third quartile is the second half of the set, any number in the set that is greater than the median. you will find the median of that half to get 65. that is your 3rd quartile. interquartile range ius the difference bewteen your first and third quartile. 65-56 is 9. hope this helped marck as brainlyest and help me with my que tooo :)