Question

Statistic - Use the values in the contingency table to solve the equation given.

Answer 1

Answer:

Step-by-step explanation:

$\begin{array}{c|c|c|c}&D&E&Sum\\---&---&---&---\\A&10&20&30\\B&15&5&20\\C&30&15&45\\---&---&---&---\\Sum&55&40&95\\\end {array}\\\\\\1) P(E)=\dfrac{40}{95} =\dfrac{8}{19} \\\\2) P(B \cup D)=P(B)+P(D)-P(B \cap D)=\dfrac{20}{95} +\dfrac{55}{95} -\dfrac{15}{95} =\dfrac{60}{95} =\dfrac{12}{19} \\\\3) P(A \cap E)=\dfrac{20}{95}=\dfrac{4}{19} \\\\4) P(B | E)=\dfrac{P(B \cap E )}{P(E)} =\dfrac{\dfrac{5}{95} }{\dfrac{40}{95} } =\dfrac{5}{40}= \dfrac{1}{8} \\\\5) P(D|E)=0$