3 years ago

What is the formula for an ionic compound with these pairs of ions? (NH4+, N-3)

Chemistry

2 answers:

icang [17]3 years ago

7 0

Answer:

=NH7

Explanation:

nlexa [21]3 years ago

5 0

Answer:NH4NO3

Explanation:

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Consider this reaction: →2NH3g+N2g3H2g At a certain temperature it obeys this rate law: rate =2.11·M−1s−1NH32 Suppose a vessel c

enot [183]

Answer: It takes 5.89 s for the concentration of $NH_3$ to decrease by 88.0%.

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$2NH_3(g)\rightarrow N_2(g)+3H_2(g)$

As the units of rate constant is $M^{-1}s^{-1}$ , the kinetics must be second order.

Integrated rate law for second order kinetics is given by:

$\frac{1}{a}=kt+\frac{1}{a_0}$

$a_0$ = initiaal concentration = 0.590 M

a= concentration left after time t = $0.590-\frac{88}{100}\times 0.590=0.0708M$

$\frac{1}{0.0708}=2.11\times t+\frac{1}{0.590}$

$t=5.89s$

Thus it takes 5.89 seconds for the concentration of $NH_3$ to decrease by 88.0%.

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